简体   繁体   English

猫鼬聚合未返回预期结果

[英]mongoose aggregation not returning expected result

I am currently learning aggregation and some related methods, after following mongoose and mongodb docs i tried it. 在尝试了mongoose和mongodb文档之后,我目前正在学习聚合和一些相关方法。 but i am having problem. 但我有问题。

Follow.aggregate([
            { $match: { user: mongoose.Types.ObjectId(userId) } },
            { $unwind: '$followers' },
            {
                $lookup: {
                    from: 'accounts',
                    localField: 'followers',
                    foreignField: '_id',
                    as: 'followers'
                }
            },
          { $project: { name: 1, photo: 1 } },

        ]).exec((err, followers) => {
            if (err) throw err;
            console.log(followers);
            res.send(followers);
        });

I want to get the followers of that userID and select the followers names and photo, but i am only getting the objectid of the matched document 我想获取该用户ID的关注者,并选择关注者名称和照片,但我仅获取匹配文档的objectid

[ { _id: 5bfe2c529419a560fb3e92eb } ]

expected output 预期产量

 [ { _id: 5bfe2c529419a560fb3e92eb , name: 'john doe", photo: 'cat.jpg'} ]

Follow Model 跟随模型

const FollowSchema = new Schema({
    user: {
        type: Schema.Types.ObjectId,
        ref: 'Account',
        required: true,
    },
    following: [{
        type: Schema.Types.ObjectId,
        ref: 'Account',
        required: true,
    }],
    followers: [{
        type: Schema.Types.ObjectId,
        ref: 'Account',
        required: true,
    }],
});

When the $project stage is wrong you would get that result. $project阶段错误时,您将得到该结果。 Try removing it first and see the output. 尝试先将其删除,然后查看输出。 To me it seems you should have something like this there: 对我来说,您似乎应该在这里有以下内容:

{ $project: { "followers.name": 1, "followers.photo": 1 } },

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM