检查用户输入和具有多个值的字典键之间的匹配

Question

If I want to check if the inputted parameter in the checkPlayer function matches a key in dict1 and return the entire object or a specific value for the respective key, how would I change this code?

dict1 = {'Messi' : ('Argentina','Barcelona'), 'Ronaldo' : ('Portugal','Juventus'), 'Robben': ('Netherlands','Bayern')}

def checkPlayer(plyr):
    for x in dict1:
        if plyr == x:
           print(x)

checkPlayer('Messi')

I am mainly confused as to why printing x would print the players name and not the whole object. How would I print the whole object , or more specifically, just the nationality or team if a match was found. Not quite sure how to access indexes in dictionaries using for loops, it's not quite as intuitive as lists :/

Thanks guys

Answer 1

You are iterating over the keys of the dictionary and printing the key (which is the name of the player) if it was found. To get the value for that key, you can use the get method (which also allows you to specify a default if a key wasn't found in the dictionary):

dict1 = {'Messi' : ('Argentina','Barcelona'), 'Ronaldo' : ('Portugal','Juventus'), 'Robben': ('Netherlands','Bayern')}

def checkPlayer(plyr):
    print(dict1.get(plyr))

checkPlayer('Messi')

Output

('Argentina', 'Barcelona')

Furthermore, to check if a player name is in your dictionary, you can simply have if plyr in dict1 ; you don't need to iterate over all the keys. So your method can also be:

def checkPlayer(plyr):
    if plyr in dict1:
        print(plyr, dict1[plyr][1])

checkPlayer('Messi')

Output

Messi Barcelona

Answer 2

your object is a key:value the key is 'Messi' the value is 'Argentina','Barcelona' however in your print statement you only print the name of object will will return the key only without the value
to access the value you may use get() or the index of the object inside your dictionary

to get your desire result use this :

print plyr,':',dict1[plyr]

Answer 3

You can use below code:

dict1 = {'Messi' : ('Argentina','Barcelona'), 'Ronaldo' : ('Portugal','Juventus'), 'Robben': ('Netherlands','Bayern')}

checkPlayer = 'Messi'
print (dict1.get(checkPlayer,'Player not found')) # 'Player not found' will be returned if checkPLayer is not in the dict1.keys()
#result --> ('Argentina', 'Barcelona')