为什么for ... of语句中的三元运算符不起作用？

Question

I am not sure why the ternary operator is not working in this example. I have seen it used in similar ways before but I can not get it to work properly in this test. Any help would be greatly appreciated!

const numbers = [1, 2, 3, 4, 5];

console.log(includes(numbers, 4));
//This works fine
function includes(array, searchElement) {
    for (let element of array)
        if (element === searchElement)
            return true;
    return false;
}

This solution works fine but when I try to use the ternary operator I always get false.

console.log(includes2(numbers, 4));

function includes2(array, searchElement) {
    for (let element of array) {
        return (element === searchElement ? true : false);
    }
}

Answer 1

Lets add blocks and convert the conditional operator back to if :

First example:

function includes(array, searchElement) {
    for (let element of array) {
        if (element === searchElement) {
            return true;
        }
    }
    return false;
}

Second example:

function includes2(array, searchElement) {
    for (let element of array) {
        // return (element === searchElement ? true : false);
        if (element === searchElement) {
           return true;
        }
        return false;
    }
}

Note the position of the return false; statement. In the first case you return after the loop. In the second case you return inside the loop, ie the function will always terminate in the first iteration of the loop.