grep regex解决方案，用于在字符串中查找3个或更多破折号

Question

I'm trying to build a bash script that will look for the keychain folder on a mac and delete it when found using grep. The challenging part is no 2 folders are alike. An example is C0955E7D-DCA1-542B-B506-72A054DET9FA. They all contain 3 or more dashes in the name. Not sure how to grep for this using regex. While in my "~/Library/Keychain/ directory, I was thinking something like...

ls | grep "*-*-*-*"

I was thinking that * would be wildcard and look for any amount of digits that will contain at-least 3 dashes between them.

I'm also opening to using python too (since it comes preinstalled on macs) but that seemed too complicated.

Answer 1

You can try (\\w+-){3,}\\w+

Explanation :

\\w+ : word characters 1 or more times
- : hyphen
(\\w+-){3,} : some word characters followed by hyphen 3 or more times
\\w+ : word characters 1 or more times

Answer 2

this will print all directory names with 3 or more dashes

find . -type d -exec sh -c '[ $(echo {} | grep -o - | wc -l) -ge 3 ]' \; -print

Answer 3

grep ".+-.+-.+-.+" would be more accurate in your case.

. = any character
+ = one or more times (matches any character, one or more times)
(* = zero or more times)