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Rust中的无符号整数溢出

[英]Unsigned integer overflow in Rust

I am a beginner to Rust. 我是Rust的初学者。 In the code: 在代码中:

println!("{}", 4400202385408u64 * 34359738368u64);

The rust compiler gives me the following error: rust编译器给我以下错误:

error: attempt to multiply with overflow 

despite the fact that the result of the multiplication is within std::u64::MAX 尽管乘法结果在std::u64::MAX

Can someone point me to what is happening? 有人可以指出我的情况吗?

despite the fact that the result of the multiplication is within std::u64::MAX 尽管乘法结果在std :: u64 :: MAX之内

Pretty sure it's not. 可以肯定的不是。

Converting to hex, you're doing 0x40080800800 * 0x800000000. 转换为十六进制,您正在执行0x40080800800 * 0x800000000。 They're both individually well over a u32 MAX, so when you multiply them together they're well over a u64 max. 它们各自在u32 MAX上都很好,因此当您将它们相乘时,它们在u64 max上都很好。

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