如何将字典元素动态分组为列表？

Question

I have JSON file as mentioned below,
**test.json**

    {
    "header1" :
       {
           "header1_body1":
              {
               "some_key":"some_value",
                .......................
              },
          "header1_body2":
              {
                "some_key":"some_value",
                 .......................
              }

       },
    "header2":
       {
          "header2_body1":
              {
               "some_key":"some_value",
                .......................
              },
          "header2_body2":
              {
                "some_key":"some_value",
                 .......................
              }
    }
}

Would like to group the JSON content into lists as below:

header1 = ['header1_body1','header1_body2']
header2 = ['header2_body1','header2_body2']

header1, header2 can be till ....header n . So dynamically lists has to be created containing it's values as shown above.

How can i achieve this ? What's the best optimal way to approach ?

SOLUTION:

with open('test.json') as json_data:
      d = json.load(json_data)

for k,v in d.iteritems():
      if k == "header1" or k == "header2":
            globals()['{}'.format(k)] = d[k].keys()

now, header1 and header2 can be accessed as list.

for i in header1:
    print i

Answer 1

Assuming you read the JSON into a variable d (maybe using json.loads ), you could iterate over the keys (sorted?) and build the lists with the keys of current value:

for key in sorted(d.keys()):
    l = [x for x in sorted(d[key].keys())]  # using list comprehension
    print(key + ' = ' + str(l))

Answer 2

Fixing your json structure:

{
"header1" :
   {
       "header1_body1":
          {
           "some_key":"some_value"
          },
      "header1_body2":
          {
            "some_key":"some_value"
          }

   },
"header2":
    {
      "header2_body1":
          {
           "some_key":"some_value"
          },
      "header2_body2":
          {
            "some_key":"some_value"
          }
    }
}

And then loading and creating lists:

header = []

for key, value in dictdump.items():

    header.append(list(value.keys()))

for header_num in range(0, len(header)):
    print("header{} : {}".format(header_num + 1, header[header_num]))

Gives:

header1 : ['header1_body1', 'header1_body2']
header2 : ['header2_body1', 'header2_body2']

Answer 3

Once you load your json, you can get the list you want for any key by doing something like the following ( headers variable below is a placeholder for your loaded json). You don't need to convert it to a list to work with it as an iterable but wrapped it in list(...) to match the output in your question.

list(headers['header1'].keys())

If you need to actually store the list of keys for each of your "header" dicts in some sort of accessible format, then you could create another dictionary that contains the lists you want. For example:

import json

data = """{
    "header1" : {
        "header1_body1": {
             "some_key":"some_value"
             },
        "header1_body2": {
            "some_key":"some_value"
            }
        },
    "header2": {
        "header2_body1": {
            "some_key":"some_value"
            },
        "header2_body2": {
            "some_key":"some_value"
            }
        }
    }"""

headers = json.loads(data)

# get the list of keys for a specific header
header = list(headers['header1'].keys())
print(header)
# ['header1_body1', 'header1_body2']

# if you really want to store them in another dict
results = {h[0]: list(h[1].keys()) for h in headers.items()}
print(results)
# OUTPUT
# {'header1': ['header1_body1', 'header1_body2'], 'header2': ['header2_body1', 'header2_body2']}

Answer 4

You can use recursion:

d = {'header1': {'header1_body1': {'some_key': 'some_value'}, 'header1_body2': {'some_key': 'some_value'}}, 'header2': {'header2_body1': {'some_key': 'some_value'}, 'header2_body2': {'some_key': 'some_value'}}}
def flatten(_d):
  for a, b in _d.items():
    yield a
    if isinstance(b, dict):
      yield from flatten(b)

new_results = {a:[i for i in flatten(b) if i.startswith(a)] for a, b in d.items()}

Output:

{'header1': ['header1_body1', 'header1_body2'], 'header2': ['header2_body1', 'header2_body2']}

Answer 5

import json
with open('test.json') as json_data:
          d = json.load(json_data)

for k,v in d.iteritems():
    if k == "header1" or k == "header2":
          globals()['{}'.format(k)] = d[k].keys()

now, `header1` and `header2` can be accessed as list.

    for i in header1:
        print i