在python中读取和分组文本文件的内容

Question

I have a text file to read in Python

Contents

line1
line2

line3
line4
line5

line6

....

Reading:

with open(path, encoding="utf8", errors='ignore') as f1:
   contents = f1.readlines()
   print (contents)

OP:

[line1, line2,.... line6]

But I want to read the contents based on white space separating the lines.

Expected OP:

[[line1, line2], [line3,line4,line5], [line6]]

Is there a shorter approach than reading the entire contents of the file iterating through the list and then grouping based on the whitespaces. Any suggestion on the approach?

Answer 1

Something like this should do what you need:

In [8]: result = []

In [9]: with open(path, encoding="utf8", errors='ignore') as fh:
   ...:     group = []
   ...:     for l in fh:
   ...:         l = l.strip()
   ...:         if not l:
   ...:             result.append(group)
   ...:             group = []
   ...:         else:
   ...:             group.append(l)
   ...:     if group:
   ...:         result.append(group)
   ...:

In [10]: result
Out[10]: [['line1', 'line2'], ['line3', 'line4', 'line5'], ['line6']]

Or another (not as readable) oneliner version using itertools groupby

from itertools import groupby    
[g for g in [list(g) for _, g in groupby(open(path).read().splitlines(), lambda l: bool(l.strip()))] if all(g)]