[英]NodeJS can not go to the folder up to execute the command from child_process.spawn
To start WebPack (which is in the parent folder) I use Gulp, but as soon as I try to go to the parent folder in the path, I get an error. 要启动WebPack(位于父文件夹中),我使用Gulp,但是一旦我尝试转到路径中的父文件夹,就会出现错误。
Gulp 古尔普
var spawn = require('child_process').spawn;
gulp.task('_Scada2', function (done) {
spawn('webpack', [], { cwd: '../../Scada.Web/' })
.on('close', done);
});
get an error 得到一个错误
[14:20:47] '_Scada2' errored after 4.47 ms
[14:20:47] Error: spawn webpack ENOENT
at Process.ChildProcess._handle.onexit (internal/child_process.js:229:19)
at onErrorNT (internal/child_process.js:406:16)
at process._tickCallback (internal/process/next_tick.js:63:19)
Процесс завершен с кодом 1.
尝试__dirname + '../../Scada.Web/'
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.