如何从网站到Android应用程序的深层链接

Question

I have a website that is mainly used by mobile users. I want to link from the website to a separate app, which should then open on the phone (the app is already installed)

For the app, I have entered the following scheme:

 <variable name="URL_SCHEME" value="alfix_smart" />
    <variable name="DEEPLINK_SCHEME" value="https" />
    <variable name="DEEPLINK_HOST" value="domain.com" />
    <variable name="ANDROID_PATH_PREFIX" value="/" />
    <variable name="ANDROID_2_PATH_PREFIX" value="/" />
    <variable name="ANDROID_3_PATH_PREFIX" value="/" />
    <variable name="ANDROID_4_PATH_PREFIX" value="/" />
    <variable name="ANDROID_5_PATH_PREFIX" value="/" />
    <variable name="DEEPLINK_2_SCHEME" value="https" />
    <variable name="DEEPLINK_2_HOST" value="www.domain.com" />

how can I now link a button of a website to the app? What do I have to do for that? Unfortunately, I have no idea.

I hope you can help me

Answer 1

• If you want to handle deep linking in both Android and iOS, it is recommended to use Dynamic Links . With Dynamic Links , you treat on all platforms such as Android, iOS and web in a similar way. It seamlessly transits users from your mobile website to the equivalent content within your app. To see its usage example, refer to this and this .

• If you want to handle deep linking in Android only (and the app is already installed as you mentioned), in simplest approach ( Deep Links ), you can introduce your Activity as a handler of specific pattern URL s and pass the desired parameters as URL query params.

To see its usage example in details, refer to this .

In AndroidManifest.xml

<activity android:name=".YourActivity">

    <intent-filter>
        <action android:name="android.intent.action.VIEW" />

        <category android:name="android.intent.category.DEFAULT" />
        <category android:name="android.intent.category.BROWSABLE" />

        <!-- Accepts URIs that begin with "https://example.com" -->
        <data android:host="example.com" />
        <data android:scheme="https" />
    </intent-filter>

    <intent-filter>
        <action android:name="android.intent.action.VIEW" />

        <category android:name="android.intent.category.DEFAULT" />
        <category android:name="android.intent.category.BROWSABLE" />

        <!-- Accepts URIs that begin with "https://www.example.com" -->
        <data android:host="www.example.com" />
        <data android:scheme="https" />
    </intent-filter>

</activity>

In YourActivity.java:

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    Intent intent = getIntent();
    String action = intent.getAction();
    if(action.equals(Intent.ACTION_VIEW)){
        Uri data = intent.getData();
        if (data.getQueryParameter("some_param") != null && data.getQueryParameter("some_param").isNotEmpty()) {

            String param = data.getQueryParameter("some_param");
            // do what you want to do with param
        }
    }
}

Your html snippet:

<a href="https://example.com?some_param=some_value">Click Me!</a>