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Google脚本API日历/ Google表格; 如何使用来宾(姓名,电子邮件)将日历导出到Google工作表

[英]Google script API calendar/google sheets; How to export calendar to google sheet with Guests (name, email)

Working with such code to extract google calendar to sheets (code has been implemented from other sources here: 使用此类代码将Google日历提取到工作表(已从其他来源实现了代码:

function cal_to_gsht(){

  var ss = SpreadsheetApp.openById( ' id_gsheet ' ), // Id is set to file 'CAL-to-gsheets' in LPRMF dir
      sheet = ss.getActiveSheet(),
      cals = [' cal1 ', ' cal2 '], c, cal, calName,

 //??     cals = getAllCalendars(),

      today = new Date(),
      start = new Date( today ), end = new Date( 'Dec 31, 2019' ),
      events, i, details,
      eventslog = [], e,
      rows = [], range;

  for (c = 0; c < cals.length; c += 1) {

    cal = CalendarApp.getCalendarById(cals[c]);
    calName = cal.getTitle();
    events = cal.getEvents(start, end);

    // add the events of the current calendar to the array of all events
    eventslog = eventslog.concat(
      events.map(function(event) {
        return {
          time: new Date(event.getStartTime()).getTime(), // sort by this
          details: [
            calName, // calNAme-change calendar info position in array to adjust
            event.getTitle(),
            event.getDescription(),
            event.getLocation(),
            event.getStartTime(),
            event.getEndTime(),
            event.addGuest()
   //         event.getGuestList()
     //       event.getGuestByEmail(0)
          ]
        };
      })
    );
  }

  // sort array of event so date order can be either way by reversing a & b
  eventslog.sort(function(a, b) { return a.time - b.time; });

  rows = eventslog.map(function(entry) { return entry.details; });

  range = sheet.getRange(2, 1, rows.length, 7);  // no. of event.details ; increase if more event.get
  range.setValues(rows);
}

How to add to event. 如何添加到事件。 another record which will be Guest name and/or email. 另一个记录将是来宾姓名和/或电子邮件。

please advise, 请指教,

afterwhile ... tired to extract email by getEmail(), but no success: 之后...厌倦了通过getEmail()提取电子邮件,但没有成功:

function(event) {
       var guestList=event.getGuestList();
       var email1=guestList[0]; // how to get EMAIL out of it !
       var email2=guestList[1];
        return {
          time: new Date(event.getStartTime()).getTime(), 
          details: [
            calName,
            event.getTitle(),
            event.getDescription(),
            event.getLocation(),
            event.getStartTime(),
            event.getEndTime(),
            email1,
            email2

          ]
        };
      })

how getEmail() works? getEmail()如何工作?

found solution, required little advanced approach to arrays, mapping them and joining again two: 找到解决方案,几乎不需要对数组进行高级处理,将它们映射并再次连接两个:

function(event) {  
        return {
          time: new Date(event.getStartTime()).getTime(),
          details: [
            calName,
            event.getTitle(),
            event.getDescription(),
            event.getLocation(),
            event.getStartTime(),
            event.getEndTime(),
            event.getGuestList().map(function(x) {return x.getEmail();}).join(',')
          ]
        };

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