[英]Typescript : Can't set default parameter value as false
I've a method which has some optional parameters, like this,我有一个有一些可选参数的方法,像这样,
initializeInteraction(opts: { type?: string; freehand?:boolean= false }) {
this._draw = this.drawService.initDraw({ drawtype: opts.type });
this._drawInteraction = this._draw.interaction;
this.mapService.addVector(this._draw.vector);
this.mapService.addInteraction(this._drawInteraction);
}
I want to set the value of freehand
as true
only when needed, otherwise I want it as false
,我只想在需要时将freehand
的值设置为true
,否则我希望它为false
,
but when i declare this但是当我宣布这个
initializeInteraction(opts: { type: string; freehand?:boolean= false }) {}
Im getting an error as我收到一个错误
[ts] A type literal property cannot have an initializer. [1247]
You just need to set the default value of freehand no need for ?
你只需要设置 freehand 的默认值就可以了 不需要?
it's already optional consider this它已经是可选的考虑这个
function initializeInteraction(type: string, freehand: boolean = false) {
console.log(type,freehand);
// your magic
}
initializeInteraction('something');
initializeInteraction('something', false);
initializeInteraction('something', true);
the only advantage of making the parameters as object is you can pass them with different order将参数作为对象的唯一优点是您可以以不同的顺序传递它们
function initializeInteraction(opt:{ type:string , freehand?:boolean}) {
let { type, freehand = false } = opt;
console.log(type,freehand);
// your magic
}
you can short the function above like this你可以像这样缩短上面的功能
function initializeInteraction({type,freehand=false }: {type:string,freehand?:boolean}) {
console.log(type,freehand);
// your magic
}
pass the parameter as object将参数作为对象传递
initializeInteraction({ type: 'something', freehand: false });
initializeInteraction({freehand: false, type: 'something' });
initializeInteraction({type: 'something' });
both ways will give the same result, but they call initializeInteraction differently两种方式都会给出相同的结果,但它们调用 initializeInteraction 的方式不同
f(''),f('',true)
or ({type:'',freehand:true}) f({freehand:true,type:''}), f({type:''})
f(''),f('',true)
或({type:'',freehand:true}) f({freehand:true,type:''}), f({type:''})
Do you really need to wrap type
and freehand
up in the opts
object?您真的需要在opts
对象中包装type
和freehand
up 吗?
I'd suggest this:我建议这样做:
initializeInteraction(type: string, freehand?: boolean = false) {
this._draw = this.drawService.initDraw({ drawtype: type });
this._drawInteraction = this._draw.interaction;
this.mapService.addVector(this._draw.vector);
this.mapService.addInteraction(this._drawInteraction);
}
would work for the current implementation of initializeInteraction
.将适用于initializeInteraction
的当前实现。
Edit:编辑:
The other option would be to use overloads...另一种选择是使用重载......
initializeInteraction(type: string);
initializeInteraction(freehand: boolean);
initializeInteraction(type: string, freehand: boolean);
initializeInteraction(param1: string | boolean, param2: boolean = false) {
//type checking and implementation here...
}
This would allow you to pass either one of your values alone, or both.这将允许您单独传递一个值,或同时传递两个值。
{ type: string; freehand?: boolean = false }
This type literal performs the same role as an interface and therefore can't provide a default value.此类型文字执行与接口相同的角色,因此不能提供默认值。 Fortunately, the value of freehand
will be undefined (falsey) by default.幸运的是,默认情况下freehand
的值将是未定义的(假的)。
You can safely replace this with您可以安全地将其替换为
initializeInteraction(opts: { type?: string; freehand?:boolean }) {
// ...
if (opts.freehand) {
// Do stuff
}
}
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