OSError：尝试从s3获取图像并打开图像时，无法识别图像文件<_io.BytesIO对象位于0x00000198001B9E08>

Question

I'm trying to get a jpeg. from s3 bucket but I'm getting an error. Here is a part of the code:

s3_client = boto3.client('s3')
bucket = os.environ['encryption_bucket']

def encrypt_zip(event, contex):
    image_key = event['keys']
    response = s3_client.get_object(Bucket= bucket, Key=image_key)
    if response['ResponseMetadata']['HTTPStatusCode'] == 200:
        object_data = response['Body']._raw_stream.data
        print(type(object_data))
        image = Image.open(io.BytesIO(object_data))

error:

OSError: cannot identify image file <_io.BytesIO object at 0x00000198001B9E08>

second question: Try to download an object from an s3 bucket and save that image

if 's3' in event['Records'][0]:
    s3  = event['Records'][0]['s3']
    image_key  = s3['object']['key']
    key_split = str(image_key).split('/')
    job_key = "-".join(key_split)
    bucket = s3['bucket']['name']
    with open(job_key, 'wb') as data:
         client.download_fileobj(bucket, image_key, data)
         set_log("logo image loaded successfully....", False)
    image_path = '/tmp/' + job_key
    image = Image.open(job_key)
    image.save(image_path)

ERROR : OSError: cannot identify image file '8093-C8FE-2403-490B-9050e99b-53a9-4e2f-b9af-9910d5fc9a0f.jpg'

and the download image in local. it is cant loaded. enter image description here

Answer 1

Based on your other questions (since deleted?), your requirements are:

• An array of filenames are passed into the function
• Convert / into - to simplify the filename
• You wish to create a zip file with these files

Therefore, it would be something like:

import boto3
import zipfile

s3_client = boto3.client('s3')
bucket = os.environ['encryption_bucket']

def encrypt_zip(event, context):
    key_array = [key.replace('/', '-') for key in event['keys']]

    # Download objects
    for key in key_array:
        response = s3_client.download_file(bucket, key, '/tmp/' + key)

    # Zip objects
    with ZipFile('/tmp/foo.zip', 'w') as myzip:
        for key in key_array:
            myzip.write('/tmp/' + key)
        myzip.close()

    # Put zip file in S3
    s3_client.upload_file('/tmp/foo.zip', bucket, 'foo.zip')

(I haven't tested this, and I just copied the Zipfile code from the documentation so I'm not sure if it is correct.)

I'm also not sure what you're trying to do with the / and - thing, because it depends upon the list of keys being passed in and what the objects are called in S3.