在使用typescript声明类私有变量时是否可以使用destrecturing？

Question

Normally when multiple variables are come from the same object I would use

const [ foo, bar, foobar ] = [ 'foo', 'bar', 'foobar' ]

But in type script, things like

class Test {
    private {a,b,c} = tool;
}

It doesn't work any more.

Is there a other way?

Answer 1

You can use Object.assign to achive the same result...

class Test {
    private a: number;
    private b: string;
    private c: boolean;

    constructor(arg: { a: number, b: string, c: boolean}) {
        Object.assign(this, arg);
    }
}

const tool = {
    a: 5,
    b: 'str',
    c: true
}

const test = new Test(tool);

console.log(JSON.stringify(tool));

The feature to destructure paramters is still active in discussion on GitHub .