[英]select statement from SQL into PHP array
The following PHP code, I tried to retrieve some values from the table by "word" column which happy, like, free and help are in this column.以下 PHP 代码,我尝试通过“word”列从表中检索一些值,这些值在此列中包含快乐、喜欢、免费和帮助。
while($row=mysqli_fetch_array($result_kwp,MYSQLI_ASSOC))
{
$v_kw = $row["word"]." ";
echo $v_kw;
}
$category_text = array(
'positive' => $v_kw,
);
echo "<b>positive</b> Category: ". $category_text['positive']."<br/>";
my output:我的输出:
happy like free help
positive Category: help
my question is why $category_text['positive'] is contained only help word?我的问题是为什么 $category_text['positive'] 只包含帮助词? How can I put every word in this array?
我怎样才能把每个单词都放在这个数组中?
In your code, every iteration reassigns $v_kw
to the new $row["word"]
.在您的代码中,每次迭代都会将
$v_kw
重新分配给新的$row["word"]
。 You have to concatenate all your results by using .=
您必须使用
.=
连接所有结果
$v_kw = "";
while($row=mysqli_fetch_array($result_kwp,MYSQLI_ASSOC))
{
$v_kw .= $row["word"]." ";
echo $row["word"];
}
$category_text = array(
'positive' => $v_kw,
);
echo "<b>positive</b> Category: ". $category_text['positive']."<br/>";
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