插入多个相同的输入名称字段Codeigniter

Question

id userid fldWorkHistoryCompanyName fldWorkHistoryJoiniedDate
1 1 abc company 2016.12.03
2 1 def company 2017.12.03
3 1 ghi company 2018.12.03
4 2 ask company 2014.12.03

 <input name="fldWorkHistoryCompanyName[]" type="text" class="form-control" placeholder="ABC Privet Limited 1" > <input type="text" class="form-control" name="fldWorkHistoryJoiniedDate[]" > <input name="fldWorkHistoryCompanyName[]" type="text" class="form-control" placeholder="ABC Privet Limited 2" > <input type="text" class="form-control" name="fldWorkHistoryJoiniedDate[]" > <input name="fldWorkHistoryCompanyName[]" type="text" class="form-control" placeholder="ABC Privet Limited 3" > <input type="text" class="form-control" name="fldWorkHistoryJoiniedDate[]" > 

how to insert multiple name filed in codeigniter

Answer 1

In order to insert multiple input text values in database using single name.

You can make a form with method POST and put these fields into form and when you submit the button you can put the action into your controller.

In the controller, you can do

$history[] = $_Post['fldWorkHistoryCompanyName'];

foreach ($history as $key => $value) {
  // make insert query and your value is in the $value variable.
}

OR

If you have active records then you can to do this:

$data = array(
   array(
      'userid' => '1' ,
      'fldWorkHistoryCompanyName' => 'Name' ,
      'fldWorkHistoryJoinedDate' => 'My date'
   ),
   array(
      'userid' => '2' ,
      'fldWorkHistoryCompanyName' => 'Another Name' ,
      'fldWorkHistoryJoinedDate' => 'Another date'
   )
);

$this->db->insert_batch('mytable', $data);

Answer 2

try this:

$fldWorkHistoryCompanyName = $this->input->post('fldWorkHistoryCompanyName');
foreach ($fldWorkHistoryCompanyName as $value) {
    $data = array(
        'field_name' => $value
    );
    $this->db->insert('tableName',$data);
}

Answer 3

you can try this solution :

$i = 0
Foreach($fldWorkHistoryCompanyName as $key=>$value)
{
    $data[$i]['fldWorkHistoryCompanyName'] = $value;
    $data[$i]['fldWorkHistoryJoiniedDate'] = $fldWorkHistoryJoiniedDate[$key];
    $i++;
}      
$this->db->insert_batch('table_name',$data);