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R中带有grepl函数的嵌套ifelse

[英]Nested ifelse with grepl function in R

i'm trying to lookup in 3 diff excel sheets(Data Frames) to add 3 new columns in the consolidated data frame. 我正在尝试在3个差异excel工作表(数据框架)中查找,以在合并的数据框架中添加3个新列。

df = Consolidated Data Frame where i'm trying to create 3 new columns df =合并数据框,我正在尝试创建3个新列

df2 = data frame(single column) where i'm looking up to get SheetName1 Column in df(SheetName1 column should result if df2 string found in any 5 columns from df else "NA" df2 =数据框(单列),我在其中查找df中的SheetName1列(如果在df中的任何5列中找到df2字符串,则应生成SheetName1列,否则为“ NA”

df3 = ddata frame(single column) where i'm looking up to get Segregation & segregationRef Column in df(Segregation column should result if df3 string found in any 5 columns from df else "NA" segregationRef column should result "NA" if string found in segregation column. I tried the below but not getting the optimum result. df3 = ddata frame(单列),我在其中查找df中的Segregation&segregationRef列(如果在df的任何5列中找到df3字符串,则应产生Segregation列,否则,如果字符串,则“ NA” segregationRef列应产生“ NA”我尝试了以下操作,但未获得最佳结果。

df <- data.frame(Section=c("sheet1", "sheet11", NA, "sheet15"),
                 Level =c("(Level 1)", "(Level 1)", "sheet1", "(Level 1)", NA),
                 SAC=c(NA, NA, "sheet5", NA), 
                 Name=c(NA, "rohan", "vaibhav", "suresh"), 
                 COLL MGR=c(NA, NA, NA, "suresh"))

df2 <- data.frame(sheetname=c("sheet1", "sheet2", "sheet3", "sheet4"))
df3 <- data.frame(segregation=c("john", "naren", "suresh", "rohan"))
df$Sheetname1 <- "NA"

for (j in 1:nrow(df2)) {
  for (k in 1:nrow(df)) {
    df$Sheetname1[k]= 
      ifelse(grepl(df2$Sheetname[j],
                   paste(df$`Level`[k], df$SAC[k]), 
                   ignore.case=T),
             df2$Sheetname[j], df$Sheetname1[k])
  }
}

df$Segregation <- NA

for(l in 1:nrow(df3)){
  for(m in 1:nrow(df)){
    df$Segregation[m]=
      ifelse(grepl(df3$Segregation[l],
                   paste(df$`Level`[m], df$Name[m], 
                         df$COLL MGR[m], 
                         df$`COLL MGR`[m], 
                         df$`Collateral Manager`[m]),
                   ignore.case=T),
             df3$Segregation[l],
             df$Segregation[m])
  }
}

Try this. 尝试这个。 It should work. 它应该工作。 Note that it will just return the first match that it finds. 请注意,它只会返回找到的第一个匹配项。

df <- data.frame(Section = c("sheet1", "sheet11", NA, "sheet15"),
                 Level =c("(Level 1)", "(Level 1)", "sheet1", "(Level 1)"), 
                 SAC = c(NA, NA, "sheet5", NA), 
                 Name = c(NA, "rohan", "vaibhav", "suresh"), 
                 `COLL MGR` = c(NA, NA, NA, "suresh") )
df2 = data.frame(sheetname = c("sheet1", "sheet2", "sheet3", "sheet4")); 

df3 = data.frame(segregation = c("john", "naren", "suresh", "rohan"))

sheetname1<-apply(df,1,function(x){
  if(any(x %in% df2$sheetname))
    return(x[x %in% df2$sheetname][1])
  else
    return(NA_character_)
})


segregation<-apply(df,1,function(x){
  if(any(x %in% df3$segregation))
    return(x[x %in% df3$segregation][1])
  else
    return(NA_character_)
})

cbind(df,sheetname1,segregation)
#output:
# Section     Level    SAC    Name COLL.MGR sheetname1 segregation
# 1  sheet1 (Level 1)   <NA>    <NA>     <NA>     sheet1        <NA>
# 2 sheet11 (Level 1)   <NA>   rohan     <NA>       <NA>       rohan
# 3    <NA>    sheet1 sheet5 vaibhav     <NA>     sheet1        <NA>
# 4 sheet15 (Level 1)   <NA>  suresh   suresh       <NA>      suresh

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