[英]how to run a python file in a package from Idle?
I have a folder (python package): 我有一个文件夹(python软件包):
app/
__init__.py
bases.py
store.py
in store.py
I have a the the code 在
store.py
我有一个代码
from .bases import BaseStore
class Store(BaseStore):
# .. class
Everything works when I run the full project. 当我运行整个项目时,一切正常。
How can I run the store.py
file itself? 我如何运行
store.py
文件本身? Running the file with Idle gives an import error. 使用空闲运行文件会导致导入错误。
How can I run a script in idle which will be aware to its package? 我如何在空闲状态下运行一个脚本,该脚本会对其软件包有所了解?
I am pretty sure that this is not an IDLE issue but one of the interaction between relative imports, sys.path, the current working directory, and how you start python. 我很确定这不是一个IDLE问题,而是相对导入,sys.path,当前工作目录以及如何启动python之间的交互之一。 To find out for sure, add the following at the top of
store.py
. 为了确定这一点,请在
store.py
顶部添加以下store.py
。
import os, sys
print(os.getcwd())
print(sys.path)
Then run your code the two different ways. 然后以两种不同的方式运行您的代码。 Also add, at a command line
同时在命令行中添加
python /path/to/app/store.py
This list is the equivalent of how IDLE runs your code. 此列表等效于IDLE如何运行您的代码。
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