无法获取__file__ Python的实际目录

Question

I've been trying to get the location of an open .py file (using Spyder) that will be used to link various files and use the __file__ name so that any machine can run from its current directory.

The problem is that when I try:

location = os.path.abspath(os.path.dirname(__file__))

It gives me the error:

NameError: name '__file__' is not defined

I bypassed this by calling on the file as a string rather than the name file variable using:

location = os.path.abspath(os.path.dirname('__file__'))

This worked for getting me the parent directory of the file but not the actual folder that the file was in:

location = 'C:\Users\......\Scripts'

When really the location is in:

location = 'C:\Users\......\Scripts\ISO'

I've tried various combinations of abspath and dirname and realpath to get the true directory that the file is in but I cannot get it.

What am I doing incorrectly?

Answer 1

Because I was running the script inside the Spyder shell it did not output the proper working directory because the working directory settings were somehow misaligned with the file's path.

This can be solved by Run -> Configuration per file -> The directory of the file being executed

But the more effective way of running the script using __file__ is to run the script from the python3.X.exe file in the directory which the script is located.