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如何使用LambdaMetaFactory实例化对象?

[英]How to instantiate an object using LambdaMetaFactory?

I have an interface Action: 我有一个接口Action:

package action;

public interface Action {
    public String act();
}

Class SimpleAction: 类SimpleAction:


package action;

public class SimpleAction implements Action {

    String action;
    public SimpleAction() {}

    public SimpleAction(String x) {
        this.action = x;
    }

    @Override
    public String act() {
        return "Act method from -" + this.action;
    }
}

Class ComplexAction: 类ComplexAction:



    package action;

    public class ComplexAction implements Action{

        String action;
        public ComplexAction() {}
        public ComplexAction(String x) {
            this.action = x;
        }
        @Override
        public String act() {
            return "Act method from -" + this.action;
        }
    }

I want to create a function which takes the name of class and returns an object of that class. 我想创建一个使用类名称并返回该类对象的函数。 This is what I have so far in my function - 这是我到目前为止的功能-

 

    public static Action resultOfActMethod(String objclass){   
        Class clazz = Class.forName(objclass);
        MethodHandles.Lookup lookup = MethodHandles.lookup();
        MethodHandle mh = lookup.findConstructor(clazz,MethodType.methodType(void.class, String.class));
    }

Figured it out. 弄清楚了。

public static Action resultOfActMethod(String objclass){    
    Class clazz = Class.forName(objclass);
    MethodHandles.Lookup lookup = MethodHandles.lookup();
    MethodHandle mh = lookup.findConstructor(clazz, MethodType.methodType(void.class, String.class));
    Function<String, Action> constructor = (Function<String, Action>)LambdaMetafactory.metafactory(lookup, "apply",MethodType.methodType(Function.class),
                        mh.type().generic(), mh, mh.type()).getTarget().invokeExact();
    Action action = constructor.apply(objclass);
    return action;
}

You can do just this, it will give you an object, using the constructor with no arguments: 您可以做到这一点,它将使用不带参数的构造函数为您提供一个对象:

public static Object resultOfActMethod(String objclass) 
    throws ClassNotFoundException, IllegalAccessException, InstantiationException, NoSuchMethodException, InvocationTargetException {
  Class<?> clazz = Class.forName(objclass);
  return clazz.getConstructor().newInstance();
}

But if possible in your application, you should make a function which takes a class instead like this: 但是,如果可能的话,您应该在应用程序中创建一个采用类的函数,如下所示:

public static <C> C resultOfActMethod(Class<C> clazz) 
    throws IllegalAccessException, InstantiationException, NoSuchMethodException, InvocationTargetException {
  return clazz.getConstructor().newInstance();
}

This is typesafe. 这是类型安全的。 You can use a specific return type. 您可以使用特定的返回类型。 This will avoid a type cast at the caller's side. 这样可以避免在调用方使用强制类型转换。

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