[英]Javascript async await not waiting for mongoose await
I am trying to move database calls out of my controller to clean things up and make them testable. 我试图从我的控制器中移出数据库调用来清理并使它们可测试。 When they are in the controller, everything moves smoothly.
当他们在控制器中时,一切都顺利进行。 I moved them out of the controller and added an async to ensure that we wait.
我将它们移出控制器并添加了异步以确保我们等待。 Otherwise, I would call the
res.render()
function within the .exec()
of Users.findOne()
. 否则,我会打电话的
res.render()
的函数内.exec()
的Users.findOne()
Now, once I am using async/await, the function in my controller thinks that there is no user because it is not waiting. 现在,一旦我使用async / await,我的控制器中的函数认为没有用户,因为它没有等待。
There are several questions on SO regarding async await, but I did not find one that resolves my issue. 有关异步等待的SO有几个问题,但我没有找到解决我的问题的问题。 I did verify that my User is returned, and I added console logs to show the path.
我确实验证了我的用户已退回,并且我添加了控制台日志以显示路径。
Assume we are resolving the route /users
假设我们正在解决路线
/users
routes/index.js 路线/ index.js
// requires & other routes not shown
router.get('/users', controller.testUserShow);
controllers/index.js 控制器/ index.js
// requires & other routes not shown
exports.testUserShow = async (req, res, next) => {
if (req.user) { // if code to get user is right here, with no async/await, the user is found and the code continues
try {
found = await services.fetchUser(req.user._id)
console.log("I am not waiting for at testusershow")
console.log(found); //undefined
// go on to do something with found
} catch(e) {
throw new Error(e.message)
}
}
}
services/index.js 服务/ index.js
const db = require('../db')
exports.fetchUser = async (id) => {
try {
console.log("fetchUser is asking for user")
return await db.returnUser(id)
} catch(e) {
throw new Error(e.message)
}
}
db/index.js DB / index.js
const User = require('../models/user');
exports.returnUser = async (id) => {
User.findById(id)
.exec(function(err, foundUser) {
if (err || !foundUser) {
return err;
} else {
// if this was in the controller
// we could res.render() right here
console.log("returnUser has a user");
console.log(foundUser); // this is a User
return foundUser;
}
});
}
The console log goes 控制台日志
fetchUser is asking for user
I am not waiting for at testusershow
undefined
returnUser has a user
// not printed... valid user
I would expect the initial call to be undefined if I was calling something that did not return a promise, but User.findOne()
should. 如果我调用的东西没有返回一个promise,我会期望初始调用是未定义的,但
User.findOne()
应该。
What am I missing here? 我在这里错过了什么?
This is the simplest way: 这是最简单的方法:
const User = require('../models/user');
exports.returnUser = (id) => {
return User.findById(id).exec().then(foundUser => {
console.log(foundUser); // this is a User
return foundUser;
});
}
if you want to use async/await then you can do: 如果你想使用async / await那么你可以这样做:
exports.returnUser = async id => {
const foundUser = await User.findById(id).exec();
console.log({foundUser});
return foundUser;
});
}
and if you wanted to use callbacks, it would look like: 如果你想使用回调,它看起来像:
exports.returnUser = (id, cb) => {
return User.findById(id).exec(cb);
}
the cool think about Mongoose is that if you don't pass a callback it will return a promise from the exec function/method. 很酷的想想Mongoose就是如果你没有传递一个回调,它会从exec函数/方法返回一个promise。
Your db/index
should be like this: 你的
db/index
应该是这样的:
exports.returnUser = (id) => {
return User.findById(id);
}
When you don't call exec, it will return a promise. 当你不调用exec时,它将返回一个promise。 And as your
services/index.js
already uses await
to get the response, db/index
doesn't need to be an async function. 并且由于您的
services/index.js
已经使用await
来获取响应,因此db/index
不需要是异步函数。
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