如何将numpy数组从numpy.int64转换为datetime？

Question

I have the following array of type <class 'numpy.ndarray'>

array([20181010, 20181031, 20181116, 20181012, 20181005, 20181008,
       20181130, 20181011, 20181005, 20181116])

How can I convert its constituents from the current type <class 'numpy.int64'> to datetime in numpy ? I want to find a quick way and my understanding is that using a loop or list comprehension, as well as converting this numpy.array to pandas or to a list will be slower.

Please correct me if I am wrong.

PS This question may have been answered somewhere, but I could not find a single solution which works.

Answer 1

pandas has a better concept of what can be considered a date:

import numpy as np
import pandas as pd
arr = np.array([20181010, 20181031, 20181116, 20181012, 20181005, 
                20181008, 20181130, 20181011, 20181005, 20181116])
pd.to_datetime(arr.astype(str)).values

Running this over a set of 10,000,000 entries:

%%prun import numpy as np; import pandas as pd
lst = [20181010, 20181031, 20181116, 20181012, 20181005, 
       20181008, 20181130, 20181011, 20181005, 20181116]*1000000
arr = np.array(lst)
arr_str = arr.astype(str)
pd.to_datetime(arr_str).values

produces a prun of

   ncalls  tottime  percall  cumtime  percall filename:lineno(function)
        1    8.977    8.977    8.977    8.977 {method 'astype' of 'numpy.ndarray' objects}
        1    4.394    4.394    4.394    4.394 {built-in method pandas._libs.tslib.array_to_datetime}
        2    2.344    1.172    2.344    1.172 {built-in method pandas._libs.algos.ensure_object}
        4    0.918    0.229    0.918    0.229 {built-in method numpy.core.multiarray.array}
        1    0.313    0.313    7.053    7.053 datetimes.py:106(to_datetime)
...

It's efficient enough.