[英]MySQL NOT IN query giving wrong results
select count(*) from call_log
where relation_id in (14,15)
and date(from_unixtime(created_time/1000)) = '2018-12-10';
Result : 1600 结果:1600
select count(*) from call_log
where relation_id in (14,15)
and date(from_unixtime(created_time/1000)) = '2018-12-10'
and id not in (NULL);
Result : 0 结果:0
select count(*) from call_log
where relation_id in (14,15)
and date(from_unixtime(created_time/1000)) = '2018-12-10'
and id in (NULL);
Result : 0 结果:0
Ideally, sum of results for query 2 an 3 should be equal to result of query 1. Or there is some issue while comparing with NULL. 理想情况下,查询2和3的结果总和应等于查询1的结果。或者与NULL比较时存在一些问题。
IN()
can not handle NULL
values. IN()
无法处理NULL
值。 Instead use IS
改为使用
IS
and id is not NULL
or 要么
and id is NULL
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