Python：如何根据字符串中单词的数量将字符串拆分为变量？

Question

I have a string like:

text = The Black Cat is running 

and I want to split the text into words and create a variable for each word without setting it manually. some thing like this:

one="The"
two="black"
three="Cat"
four="is"
five="running"

but if there is a different string with more or fewer words it will create an amount of variables according to the amount of words; for example, if there are seven words it will create seven variables.

Answer 1

You can have a dictionary and create the variables on the fly for each value in text :

So, you don't have to worry about larger strings. It will create n number of variables depending upon its length.

In [2355]: d = {}
In [2357]: for c,i in enumerate(text.split()):
      ...:     d['var{}'.format(c)] = i
      ...:     
      ...:     

In [2358]: d
Out[2358]: 
{'var0': 'The',
 'var1': 'Black',
 'var2': 'Cat',
 'var3': 'is',
 'var4': 'running'}

Then, you can access the dictionary like below:

In [2362]: for key in d.keys():
      ...:     print(key,d[key])
      ...:     
('var4', 'running')
('var1', 'Black')
('var0', 'The')
('var3', 'is')
('var2', 'Cat')

Answer 2

Just unpack the values, for example:

text = "The Black Cat is running"

one, two, three, four, five, *_ = l = text.split()

for n in l:
  print(n)

Notice the usage of *_ in case the resulting split has more words than desired. In case it has less it will always fail.

Here you have the live example

Answer 3

suppose we have this string

str = "The Black Cat is running"

then we need to split it to get all array elements of the string as:

str_arr = str.split(" ") 

str_arr = ['The', 'Black', 'Cat', 'is', 'running']

To persist the dynamic variable's value, we can use Hash:

 mydict = {}

And then we need to iterate the array and assign the element to the unique variable as below:

for index in range(len(str_arr)):
  mydict["var_%d" %index] = str_arr[index]
  print "var_%d : " %index + str_arr[index]

which will give the output as:

var_0 : The

var_1 : Black

var_2 : Cat

var_3 : is

var_4 : running

And to print Hash, we can write:

print mydict
{'var_0': 'The', 'var_1': 'Black', 'var_2': 'Cat', 'var_3': 'is', 'var_4': 'running'}

Hope, this will provide some hint to write to your next logic..

Answer 4

I read this as two different questions.

1. Split each word in the string into a separate variable

You can do this very simply with the .split() method for strings. As answered above

text = "The Black Cat is running"
one, two, three, four, five, *_ = l = text.split()

2. Count the letters of each word

One way that you could approach this is to first sort the words by the number of letters they have, and then second to assign them to proper variables. For instance

def count_letters_in_each_word(text):
    word_counts = {len(word): word for word in text.split(' ')}
    max_length = max(word_counts.keys())
    return [word_counts.get(cnt) for cnt in range(1, max_length+1)]

text = 'The Black cat is flopping around'
one, two, three, four, five, six, seven, eight = count_letters_in_each_word(text)
print(one)
> None
print(five)
> "Black"
print(seven)
> None
print(eight)
> "flopping"

# or, if you only want short words
one, two, *_ = count_letters_in_each_word(text)

Answer 5

The best way to deal this problem would be to use list of dict instead. But for some reasons, if you want to create variables as you mentioned then this might help

text = "The Black Cat is running "
text=text.strip().split(" ")

for i,j in enumerate(text,1):
    locals()['var'+str(i)]=j # create variable as var1='The' and so on in local scope

Trying accessing the variables

print(var1,var2,var3,var4,var5)

Output

('The', 'Black', 'Cat', 'is', 'running')