[英]Laravel 5.7 - Undefined offset: 1
I'm new in Laravel and it is my first question. 我是Laravel的新手,这是我的第一个问题。 I have 3 tables:
我有3张桌子:
categories: id, name (at the moment 2 items) 类别:ID,名称(目前有2个项目)
variants: id, name 变体:id,名称
category_variant: id, category_id, variant_id; category_variant:id,category_id,variant_id; <-- Every variant has 1 or 2 categories
<-每个变体都有1或2个类别
In the VariantController I have following code: 在VariantController中,我有以下代码:
public function edit($id)
{
$variant = Variant::where('id', $id)->with('categories')->first();
$categories = Category::all();
return view('admin.variant.edit', compact('variant', 'categories'));
}
In the edit.blade.php I have following html: 在edit.blade.php中,我有以下html:
@foreach ($categories as $key=>$category) <div class="form-group form-float"> @if (isset($variant->categories[$key]->pivot->category_id)) <-- I think here is the problem <input type="checkbox" id="wb" class="filled-in" name="wb" value="{{$category->id}}" {{ $category->id == $variant->categories[$key]->pivot->category_id ? 'checked' : ''}} > <label for="wb">{{ $category->name}}</label> @else <input type="checkbox" id="wb" class="filled-in" name="wb" value="{{$category->id}}"> <label for="wb">{{ $category->name}}</label> @endif </div> @endforeach
I want to know which category was checked in the checkbox. 我想知道在复选框中选中了哪个类别。 If the variant has all 2 categories everthing is ok but if the user has chosen only one category I get an error
如果该变体具有所有2个类别,则一切正常,但是如果用户仅选择一个类别,则会出现错误
Undefined offset: 1 (View: /shui/resources/views/admin/variant/edit.blade.php)
How can I solve this problem? 我怎么解决这个问题? Thanks in advance Dimi
在此先感谢Dimi
You can use the power of collection : 您可以使用收藏的力量:
@if($variant->categories->contains($category))
{{-- You does not need to test a second time to know if you need to "check" --}}
<input type="checkbox" id="wb" class="filled-in" name="wb" value="{{$category->id}}" checked >
<label for="wb">{{ $category->name}}</label>
@else
{{-- Do stuff --}}
@endif
Or simpler. 或更简单。 Remove the first
@if
删除第一个
@if
<input type="checkbox" id="wb" class="filled-in" name="wb" value="{{$category->id}}" $variant->categories->contains($category)? 'checked' : '' >
<label for="wb">{{ $category->name}}</label>
Also in you Controller, you can simplify 同样在Controller中,您可以简化
$variant = Variant::where('id', $id)->with('categories')->first();
with 与
$variant = Variant::with('categories')->find($id);
// Or better, Laravel throws a 404 error when the id doesn't exists
$variant = Variant::with('categories')->findOrFail($id);
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