[英]Define Object type with variable properties name in TypeScript
I'm struggling with a React + TypeScript "problem": it actually don't stop my app, but now I've this doubt I want to remove!.. It's more of a question! 我在React + TypeScript的“问题”中苦苦挣扎:它实际上并没有停止我的应用程序,但是现在我想删除这个疑问!..这更多的是问题!
What I would like to achieve is to define the properties name of an object, whereas the properties name are given by variables. 我要实现的是定义对象的属性名称,而属性名称由变量给定。 Let me explain with an example -> https://codepen.io/Gesma94/pen/xmwMzY
让我用一个例子来解释-> https://codepen.io/Gesma94/pen/xmwMzY
/* The 'data' property is "dynamic": it will always have this structure,
* but the name properties (and the values) may change.
* The 'mapping' property is used to know the name properties inside 'data'.
*/
const series = {
data: [
{map1: "People reached", map2: 200},
{map1: "People who called", map2: 117},
{map1: "Contract signed", map2: 77}
],
mapping: {
stage: "map1",
values: "map2"
}
};
/* This is the actual app. */
const myPar = document.getElementById("myPar");
const { stage: stageLabel, values: valuesLabel} = series.mapping;
series.data.forEach((sample: any, index: number) => {
myPar.innerHTML = myPar.innerHTML + "<br>" + sample[stageLabel];
});
As you can see, in the forEach
I write sample: any
. 如您所见,在
forEach
我编写了sample: any
。
Now, I know sample
has a string
(the first one will always be a string
) property which name is map1
, and that's because I retrieved and saved in stageLabel
. 现在,我知道
sample
具有一个string
(第一个始终是string
)属性,其名称为map1
,这是因为我检索并保存在stageLabel
。 I also know that the other property is a number
(it's always a number
) and its name map2
is saved in valueLabel
. 我也知道另一个属性是一个
number
(始终是一个number
),其名称map2
保存在valueLabel
。
Now, what I'm starving to understand is how to not write sample: any
, but define the type of sample
using the information I retrieved earlier. 现在,我渴望了解的是如何不编写
sample: any
,而是使用我之前检索的信息来定义sample
的类型。 Basically, I would like to write something like: sample: {stageLabel: string, valueLabel: number}
, but doing this way TypeScript believe sample
has the properties stageLabel
and valueLabel
, since we are in "compile time" and it can't even evaluate the variables. 基本上,我想编写如下
sample: {stageLabel: string, valueLabel: number}
: sample: {stageLabel: string, valueLabel: number}
,但是这样做TypeScript认为sample
具有stageLabel
和valueLabel
属性,因为我们处于“编译时”,甚至不能评估变量。
So, since TypeScript can't know what's inside the variables, I know I can't actually obtain sample: {map1: string, map2: number}
, but maybe I can obtain some sort of aliasing. 因此,由于TypeScript无法知道变量内部的内容,因此我知道实际上无法获取
sample: {map1: string, map2: number}
,但是也许我可以获得某种别名。 For example, I write sample: {stageLabel: string, valueLabel: number}
, and in the rest of the code I use the properties sample.stageLabel
and sample.valueLabel
. 例如,我编写了
sample: {stageLabel: string, valueLabel: number}
,在其余的代码中,我使用了sample.stageLabel
和sample.valueLabel
属性。 Then, when the application is running, those property name are evaluated, so sample.stageLabel
is actually sample.map1
. 然后,在应用程序运行时,将评估那些属性名称,因此
sample.stageLabel
实际上是sample.map1
。
I hope I've been clear enough to understand my question. 我希望我已经足够清楚地理解我的问题。
Why not actually map your data? 为什么不实际映射您的数据?
const series = { data: [ {map1: "People reached", map2: 200}, {map1: "People who called", map2: 117}, {map1: "Contract signed", map2: 77} ], mapping: { stage: "map1", values: "map2" } }; const myPar = document.getElementById("myPar"); let mappedData = getMappedData(series.data, series.mapping); // append results mappedData.forEach((record:{stage:string, value:number}) => { myPar.innerHTML = myPar.innerHTML + `<br>${record.stage}: ${record.value}`; }); function getMappedData(data, mapping): {stage:string, value:number}[] { let stageLabel = mapping["stage"]; let valueLabel = mapping["values"]; return data.map(x => { return { stage: x[stageLabel], value: x[valueLabel] }; }) }
<p id="myPar"><b>Results:</b></p>
Note that the compiler already nows that items in mappedData
have the type {stage:string, value:number}
, so you can omit this when appending and simply write: 请注意,编译器现在已经知道
mappedData
中的项目的类型为{stage:string, value:number}
,因此您可以在追加时忽略此内容,只需编写即可:
// append results
mappedData.forEach(record => {
myPar.innerHTML = myPar.innerHTML + `<br>${record.stage}: ${record.value}`;
});
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.