使用 for 循环打印三角形金字塔图案 python

Question

I am using the following for loop code to print star pattern and the code is working perfectly fine. Here is my code

for i in range(1,6):
    for j in range(i):
        print("*", end=" ")
    print()

Output of this code is displaying as

* 
* * 
* * * 
* * * * 
* * * * * 

Now my question is how to print output like

         * 
        * * 
       * * * 
      * * * * 
     * * * * * 

Answer 1

Actually, that can be done in a single loop:

for i in range(1, 6):
  print (' ' * (5 - i), '* ' * i)

Answer 2

This can be achieved in one loop and center padding.

n = int(input('Enter the row you want to print:- '))
sym = input('Enter the symbol you want to print:- ')
for i in range(n):
    print((sym * ((2 * i) + 1)).center((2 * n) - 1, ' '))

Answer 3

# right angle triangle
for i in range(1, 10):
    print("* " * i)

# equilateral triangle
# using reverse of range
for i , j in zip(range(1, 10), reversed(range(1, 10)):
    print(" " * j + "* " * i)

# using only range()
for i, j in zip(range(1, 10), range(10, -1, -1):
    print(" " * j + "* " * i)

Answer 4

You just need to add spaces loop ahead:

for i in range(1,6):
    for j in range(6-i):
        print(" ", end="")
    for j in range(i):
        print("*", end=" ")
    print()

Answer 5

Here is another way

size = 7
m = (2 * size) - 2
for i in range(0, size):
    for j in range(0, m):
        print(end=" ")
    m = m - 1 # decrementing m after each loop
    for j in range(0, i + 1):
        # printing full Triangle pyramid using stars
        print("* ", end=' ')
    print(" ")

Answer 6

Try this :-

Description for printing star pattern:-

1)First line is for Function to demonstrate printing pattern triangle

2)Second line is for number of spaces

3)Third line for outer loop to handle number of rows.

4)in loop inner loop to handle number spaces and values changing according to requirements.

5)After loop each loop decrementing k value.

6)After decrementing k value inner loop to handle number of columns and values changing according to outer loop.

7)printing '*' after j loop.

8)Ending line after each row

def triangle(n): 
  k = 2*n - 2
  for i in range(0, n): 


    for j in range(0, k): 
        print(end=" ") 

    k = k - 1

    for j in range(0, i+1): 

        print("* ", end="") 


    print("\r") 


n = 5
triangle(n) 

Answer 7

def triangle(val: str, n: int, type: str):
    for i in range(n):
        if type == "regular":
            print((i + 1) * val)
        elif type == "reversed":
            print((n - i) * val)
        elif type == "inverted":
            print((n - (i + 1)) * " " + (i + 1) * val)
        elif type == "inverted reversed":
            print(i * " " + (val * (n - i)))
        elif type == "triangle":
            print((n - (i + 1)) * " " + ((2*i)+1) * val) 

Call the function like this

triangle("*", 5, 'triangle')

Output

    *
   ***
  *****
 *******
********* 

Answer 8

.very simple answer.. don't go for complex codes..

first try to draw a pyramid. by * ..then u easly understand the code..my solution is.. simplest..here example of 5 lines pyramid..

number_space  =  5
for   i   in   range (5)

     print('/r')

     print (number_space *"  ", end='')

     number_space=number_space-1

     for star in range (i+1):

                print("*",end="  ")

Answer 9

Use String Multiplication, To simply multiply a string, this is the most straightforward way to go about doing it:

num = 5 for e in range(num, 0, -1): print(" " (e-1)+(" " (num-e+1))+(" "*(num-e)))

Answer 10

Late to answer. But as other mentioned, this can be done in a single loop like below

j=1
for i in range(10,0,-1):
    print(" "*i,"*"*j)
    j+=2

Answer 11

Method #1: Comprehension version

This could be easiest way to print any pattern in Python

n = 5
print('\n'.join([('* '*i).center(2*n) for i in range(1,n+1)]))

Use center method of str , give it a width as parameter and it will centered the whole string accordingly.

Method #2: Regular version

n = 5
for i in range(1,n+1):
  print(('* '*i).center(2*n))

Answer 12

Here's the easiest way to print this pattern:

n = int(input("Enter the number of rows: "))
for i in range(1,n+1):
    print(" "*(n-i) + "* "*i)

You have to print spaces (ni) times where n is the number of rows and i is for variable of loop and add it with stars i times. This will give you the desired pattern. See the above mentioned code for better understandability.

Answer 13

j=1

for i in range(5,0,-1):

print(" "*i, end="")

while j<6:
    print("* "*j)
    j=j+1
    break

Answer 14

          #n=Number of rows
          def get_triangle(n):
              space,star=" ","* "
              for i in range(1,n+1):
                   print((n-i)*space + star*i)
           
                         


          get_triangle(5)

Answer 15

function printPyramid($n)
{
    //example 1
    for ($x = 1; $x <= $n; $x++) {
        for ($y = 1; $y <= $x; $y++) {
            echo 'x';
        }
        echo "\n";
    }

    // example 2
    for ($x = 1; $x <= $n; $x++) {
        for ($y = $n; $y >= $x; $y--) {
            echo 'x';
        }
        echo "\n";
    }

    // example 3

    for($x = 0; $x < $n; $x++) {
        for($y = 0; $y < $n - $x; $y++) {
            echo ' ';
        }
        for($z = 0; $z < $x * 2 +1; $z++) {
            echo 'x';
        }
        echo "\n";
    }


}

Answer 16

#CPP Program for Print the dynamic pyramid pattern by using one loop in one line.

https://www.linkedin.com/posts/akashdarji8320_cpp-cplusplus-c-activity-6683972516999950336-ttlP

#include

using namespace std;

int main() {
    int rows;

    cout<<"Enter number of rows :: ";
    cin>>rows;

    for( int i = 1, j = rows, k = rows; i <= rows*rows; i++ )
        if( i >= j && cout<<"*" && i % k == 0 && (j += rows-1) && cout<<endl || cout<<" " );
}