两个带有 xslt 语言的“xsl:for-each”cicle 内的计数器项
[英]Counter item inside two "xsl:for-each" cicle with xslt language
问题描述
I wish I could count the total rows of the two for-each would be possible?
我希望我可以计算两个 for-each 的总行数可能吗？
The xml is: xml是：
<root xmlns="">
<General>
<Data>
<Number>123456</Number>
<Date>2018-10-22</Data>
<LineRefer>0001</LineRefer>
<LineRefer>0002</LineRefer>
</Data>
<Data>
<Number>789456</Number>
<Date>2018-10-22</Data>
<LineRefer>0003</LineRefer>
<LineRefer>0004</LineRefer>
</Data>
</General>
<Services>
<Details>
<LineNumber>0001</LineNumber>
<Description>test description</Description>
</Details>
<Details>
<LineNumber>0002</LineNumber>
<Description>test description</Description>
</Details>
<Details>
<LineNumber>0003</LineNumber>
<Description>test description</Description>
</Details>
<Details>
<LineNumber>0004</LineNumber>
<Description>test description</Description>
</Details>
</root>
this is the xsl这是 xsl
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html" />
<xsl:key name="services" match="Services/Details" use="LineNumber" />
<xsl:template match="root">
<html>
<head>
<title>HTML Document Example</title>
</head>
<body>
<div class="page">
<xsl:for-each select="General/Data" >
<h1><xsl:value-of select="Number" /></h1>
<ul>
<xsl:for-each select="key('services', LineRefer)">
<li><xsl:value-of select="LineNumber" /> | <xsl:value-of select="Description" /> </li>
<xsl:if test="(count(preceding-sibling::*) + 1) mod 40 = 0 ">
<!--here insert the pageBreak-->
</xsl:if>
</xsl:for-each>
</ul>
</xsl:for-each>
</div>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
the output is :输出是：
number 123456编号 123456
0001 | 0001 | test description测试说明
0002 | 0002 | test description测试说明
number 789456编号 789456
0003 | 0003 | test description测试说明
0004 | 0004 | test description测试说明
If I use that xsl code I know that the lines are 4, but I would like the count to return me 6 I would like to know the exact number of lines.如果我使用该 xsl 代码，我知道这些行是 4，但我希望计数返回 6 我想知道确切的行数。 At the moment I use an inaccurate system and I only count the lines of the second loop.目前我使用了一个不准确的系统，我只计算第二个循环的行数。
2 个解决方案
解决方案1
0 2018-12-17 09:03:59
you could add a variable in your outer loop with the current position and use it in your calculation您可以在当前位置的外循环中添加一个变量并在计算中使用它
<xsl:for-each select="General/Data" >
<xsl:variable name="outerPos" select="position()"/>
<xsl:for-each select="key('services', LineRefer)">
<li><xsl:value-of select="LineNumber" /> | <xsl:value-of select="Description" /> </li>
<xsl:if test="(count(preceding-sibling::*) + $outerPos) mod 40 = 0 ">
解决方案2
0 2018-12-18 12:41:36
Given a well-formed input such as:给定一个格式良好的输入，例如：
XML XML
<root xmlns="">
<General>
<Data>
<Number>123456</Number>
<Date>2018-10-22</Date>
<LineRefer>0001</LineRefer>
<LineRefer>0002</LineRefer>
</Data>
<Data>
<Number>789456</Number>
<Date>2018-10-22</Date>
<LineRefer>0003</LineRefer>
<LineRefer>0004</LineRefer>
<LineRefer>0005</LineRefer>
</Data>
</General>
<Services>
<Details>
<LineNumber>0001</LineNumber>
<Description>test description</Description>
</Details>
<Details>
<LineNumber>0002</LineNumber>
<Description>test description</Description>
</Details>
<Details>
<LineNumber>0003</LineNumber>
<Description>test description</Description>
</Details>
<Details>
<LineNumber>0004</LineNumber>
<Description>test description</Description>
</Details>
<Details>
<LineNumber>0005</LineNumber>
<Description>test description</Description>
</Details>
</Services>
</root>
the following stylesheet:以下样式表：
XSLT 1.0 XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>
<xsl:template match="/root">
<count-lines>
<xsl:value-of select="count(General/Data) + count(General/Data/LineRefer)"/>
</count-lines>
</xsl:template>
</xsl:stylesheet>
will return:将返回：
<?xml version="1.0" encoding="utf-8"?>
<count-lines>7</count-lines>
To assign a cumulative counter to each LineRefer (while including the parent Data in the count), you can do something like:要为每个LineRefer分配一个累积计数器（同时在计数中包括父Data ），您可以执行以下操作：
XSLT 1.0 XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>
<xsl:template match="/root">
<output>
<xsl:for-each select="General/Data">
<xsl:variable name="i" select="position()" />
<xsl:for-each select="LineRefer">
<xsl:variable name="j">
<xsl:number count="LineRefer" level="any"/>
</xsl:variable>
<line-num>
<xsl:value-of select="$i + $j"/>
</line-num>
</xsl:for-each>
</xsl:for-each>
</output>
</xsl:template>
</xsl:stylesheet>
to get:要得到：
Result结果
<?xml version="1.0" encoding="utf-8"?>
<output>
<line-num>2</line-num>
<line-num>3</line-num>
<line-num>5</line-num>
<line-num>6</line-num>
<line-num>7</line-num>
</output>
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