使用正则表达式分割字符串并包含模式

Question

I need to split a string on the degree (MSC, BSc,...) and keep the name with the title in column 0 and the address in column 1. Note the country code at the end BS matches the title

Please find some sample data below:

Phillipp Shuster MSc Grolmanstraße 6 28195 Bremen Bahnhofsvorstadt DE
Eric Jager BSc Mohrenstrasse 29 72362 Nusplingen DE
Nykee Peters BS Taylor Street, Duncan Town BS

I want to finish as below:

Phillipp Shuster MSc    |   Grolmanstraße 6 28195 Bremen Bahnhofsvorstadt DE
Eric Jager BSc          |   Mohrenstrasse 29 72362 Nusplingen DE
Nykee Peters BS         |   Taylor Street, Duncan Town BS

I tried this, but this adds the title to the address ( Not correct ).

splitted=re.split("\s(?=(?:msc|bsc|bs)[^$])",participants, flags=re.IGNORECASE)

Phillipp Shuster    | Msc Grolmanstraße 6 28195 Bremen Bahnhofsvorstadt DE
Eric Jager          | BSc   Mohrenstrasse 29 72362 Nusplingen DE
Nykee Peters        | BS Taylor Street, Duncan Town BS

Answer 1

You can use this mate

(?<=\bmsc)|(?<=\bbsc)|(?<=\bbs)\s

• (?<=\\bmsc) - Matches msc .
• (?<=\\bbsc) - Matches bsc .
• (?<=\\bbs) - Matches bs .
• \\s - Matches space.

Demo

Answer 2

Instead of splitting I would suggest re.subn approach:

import re

data = '''Phillipp Shuster MSc Grolmanstraße 6 28195 Bremen Bahnhofsvorstadt DE
Eric Jager BSc Mohrenstrasse 29 72362 Nusplingen DE
Nykee Peters BS Taylor Street, Duncan Town BS'''

pattern = re.compile(r'^.+? (msc|bsc|bs)', flags=re.I)

for line in data.split('\n'):
    result = pattern.subn(lambda m: '{:<20s} | '.format(m.group()), line, count=1)
    print(result[0])

The output:

Phillipp Shuster MSc |  Grolmanstraße 6 28195 Bremen Bahnhofsvorstadt DE
Eric Jager BSc       |  Mohrenstrasse 29 72362 Nusplingen DE
Nykee Peters BS      |  Taylor Street, Duncan Town BS

Answer 3

Instead of split you can use this simple regex with 2 captured group in findall :

reg = r'(?i)^(.*\s[BM]Sc?)\s+(.+)$'

RegEx Demo

RegEx Description:

• (?i) : Ignore case mode
• ^ : start
• (.*\\s[BM]Sc?) : Match 0+ characters till BSc or BS or MS or Msc in capture group 1
• \\s+ : Match 1+ whitespaces
• (.+) : Match 1+ characters until end in 2nd capture group
• $ : End

Answer 4

My 2c using re.sub :

import re
x = """Phillipp Shuster MSc Grolmanstraße 6 28195 Bremen Bahnhofsvorstadt DE
Eric Jager BSc Mohrenstrasse 29 72362 Nusplingen DE
Nykee Peters BS Taylor Street, Duncan Town BS"""

for y in x.split("\n"):
    print(re.sub("^(.*?(?:MS|BS)c?)(.*)", r"\1 |\2", y, 0, re.DOTALL))

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Output:

Phillipp Shuster MSc | Grolmanstraße 6 28195 Bremen Bahnhofsvorstadt DE
Eric Jager BSc | Mohrenstrasse 29 72362 Nusplingen DE
Nykee Peters BS | Taylor Street, Duncan Town BS

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Python Demo
Regex Demo