Android JSON获取请求

Question

I want to print the textview of the user who made the android login process, I first converted the data to json format in php, but when I type database / show.php into the android url part, the textview is typed as null.

Php code :

$id=$_GET["id"];
$sql=$conn->prepare("SELECT  id,name,surname,type FROM personel WHERE id='$id'");
$sql->execute();
$result=$sql->fetch(PDO::FETCH_ASSOC);
echo (json_encode($result));

Java code :

    final String url = "database/show.php";
    JsonObjectRequest jsonObjectRequest = new JsonObjectRequest
            (Request.Method.GET, url, null, new Response.Listener<JSONObject>() {

                @Override
                public void onResponse(JSONObject response) {

                    try {

                           if(response.equals("başarılı")) {
                               userId.setText(response.getString("id").toString());
                               userName.setText(response.getString("name"));
                               userSurname.setText(response.getString("surname"));
                               userType.setText(response.getString("type"));
                           }
                    } catch (JSONException e) {
                        e.printStackTrace();
                    }

                }
            }, new Response.ErrorListener() {

                @Override
                public void onErrorResponse(VolleyError error) {

                    Toast.makeText(getApplicationContext(), "error"+error, Toast.LENGTH_SHORT).show();
                }

            });

// Access the RequestQueue through your singleton class.

MySingleton.getInstance(this).addToRequestQueue(jsonObjectRequest);

Answer 1

I have some suggestions: 1. You are calling database, but id is null. Why don't you try database/show.php?id=2 for example, and use all the url http//../database/show.php?id=2 2. Please load json file to help you a little more

Answer 2

I see some problems with your code:

1- You didn't pass any id in your new JsonObjectRequest , So your php code doesn't GET any id probably.(should be final String url = "http://127.0.0.1/database/show.php?id=234"; )

2- You treated $id in your query as a string. id is usually an Integer.(should be WHERE id=$id )

3- The result of your query would be an array. So your client would get a JSONArray, not a JSONObject.(should be response.getJSONObject(0).getString("id").toString() )

4 - And what is if(response.equals("başarılı")) ? Comparing a JSON type with a String type?