[英]C++14 Create vector from variadic templates
Suppose, I have a structure 假设,我有一个结构
struct A
{
std::string name;
};
and want to write function which reads field "name" from objects and return them as std::vector<std::string>
. 并且想要编写从对象读取字段“name”的函数并将它们作为
std::vector<std::string>
。 Is it possible to do this by variadic templates (or any non-iterative method). 是否可以通过可变参数模板(或任何非迭代方法)来完成此操作。 My goal is something like this:
我的目标是这样的:
template<typename... Ts>
std::vector<std::string> function(Ts... ts)
{
...
}
in program: 在程序中:
A a1, a2, a3, a4;
function(a1, a2, a3, a4);
output: {a1.name, a2.name, a3.name, a4.name}
输出:
{a1.name, a2.name, a3.name, a4.name}
A really simple expansion that works in C++11: 一个非常简单的扩展,适用于C ++ 11:
template <typename ... Ts>
std::vector<std::string> function(Ts&& ... ts)
{
return {std::forward<Ts>(ts).name...};
}
(forwarding references not required) (不需要转发参考)
What happens is, that the vector is constructed with initializer list, constructed from the variadic parameter pack , while applying a function (member access operator) for each variadic element. 所发生的是,向量是用初始化列表构造的,由变量参数包构造 ,同时为每个可变元素应用函数 (成员访问运算符)。
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