如何遍历list并将每个元素作为包含自身作为唯一元素的list传递？

Question

I am interacting with an API that requires a list containing only one element be passed as a parameter.

I am trying to perform the same operation for each element in a list of elements.

This is my simple example code:

category_ids = 13
temp = svc.call(session, 'catalog_category.assignedProducts', [category_ids])

This works well.

What I would like to do is to define category_ids to have several elements, such as category_ids = [12, 13, 14, 15] and perform the call to API where [category_ids] references each element in the list.

Is this possible?

Answer 1

You could wrap this in a function (if I understand you correctly):

def my_call(category_ids):
    return [svc.call(session, 'catalog_category.assignedProducts', [category_id]) for category_id in category_ids]

Answer 2

temp = []

for category_id in category_ids:
    temp.append(svc.call(session, 'catalog_category.assignedProducts', [category_id])

After that you will have results of individual calls (for individual category_id s) in the temp list.