[英]extract string including empty values from a plain text using python
I have a string 我有一个弦
a='S
LINC SHORT LEGAL TITLE NUMBER
0037 471 661 1720278;16;21 172 211 342
LEGAL DESCRIPTION
PLAN 1720278
BLOCK 16
LOT 21
EXCEPTING THEREOUT ALL MINES AND MINERALS
ESTATE: FEE SIMPLE
ATS REFERENCE: 4;24;54;2;SW
MUNICIPALITY: CITY OF EDMONTON
REFERENCE NUMBER: 172 023 641 +71
----------------------------------------------------------------------------
----
REGISTERED OWNER(S)
REGISTRATION DATE(DMY) DOCUMENT TYPE VALUE CONSIDERATION
-----------------------------------------------------------------------------
---
172 211 342 15/08/2017 $610,000 CASH & MTGE'
Need to extract values below document type, value and consideration and output in an array like ['','$610,000','CASH & MTGE']
I tried using findall(r'(?<!\\S)(?:[$]\\S+|[^$\\d]+)\\b', a)
. 需要提取低于文档类型,值和注意事项的值,并以['','$610,000','CASH & MTGE']
等数组的形式输出,我尝试使用findall(r'(?<!\\S)(?:[$]\\S+|[^$\\d]+)\\b', a)
。 But I could only get ['$610,000','CASH & MTGE']
and no value for document type since it is empty. 但是我只能得到['$610,000','CASH & MTGE']
,文档类型没有值,因为它为空。
From what I understood, you would like to return an Array with the values $610,000 CASH & MTGE'
from the string right? 据我了解,您想从字符串中返回一个值为$610,000 CASH & MTGE'
的数组吗?
Assuming the required string value would remain in the end, we can leverage the splitlines
function. 假设所需的字符串值将保留在最后,我们可以利用splitlines
函数。 Then, use len(a)-1
to fetch the required string something like this: 然后,使用len(a)-1
来获取所需的字符串,如下所示:
>>> a='''S
LINC SHORT LEGAL TITLE NUMBER
0037 471 661 1720278;16;21 172 211 342
LEGAL DESCRIPTION
PLAN 1720278
BLOCK 16
LOT 21
EXCEPTING THEREOUT ALL MINES AND MINERALS
ESTATE: FEE SIMPLE
ATS REFERENCE: 4;24;54;2;SW
MUNICIPALITY: CITY OF EDMONTON
REFERENCE NUMBER: 172 023 641 +71
----------------------------------------------------------------------------
----
REGISTERED OWNER(S)
REGISTRATION DATE(DMY) DOCUMENT TYPE VALUE CONSIDERATION
-----------------------------------------------------------------------------
---
172 211 342 15/08/2017 $610,000 CASH & MTGE'''
>>> b=a.splitlines()
>>> req_line = b[len(b)-1]
>>> print(req_line)
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