[英]Regex expression to find strings between two strings in Python
I am trying to write a regular expression which returns a string which is between two other strings. 我正在尝试编写一个正则表达式,该表达式返回一个位于其他两个字符串之间的字符串。 For example: I want to get the string along with spaces which resides between the strings "15/08/2017" and "$610,000"
例如:我想获取字符串以及位于字符串“ 15/08/2017”和“ $ 610,000”之间的空格
a='172 211 342 15/08/2017 TRANSFER OF LAND $610,000 CASH & MTGE'
should return 应该回来
"TRANSFER OF LAND"
Here is the expression I have pieced together so far: 到目前为止,这是我拼凑的表达方式:
re.search(r'15/08/2017(.*?)$610,000', a).group(1)
It doesn't return any matches. 它不返回任何匹配项。 I think it is because we also need to consider spaces in the expression.
我认为是因为我们还需要考虑表达式中的空格。 Is there a way to find strings between two strings ignoring the spaces?
有没有办法找到两个字符串之间的字符串而忽略空格?
Use Regex Lookbehind & Lookahead
使用正则表达式
Lookbehind & Lookahead
Ex: 例如:
import re
a='172 211 342 15/08/2017 TRANSFER OF LAND $610,000 CASH & MTGE'
print(re.search(r"(?<=15/08/2017).*?(?=\$610,000)", a).group())
Output: 输出:
TRANSFER OF LAND
>>> re.search(r'15/08/2017(.*)\$610,000',a).group(1)
' TRANSFER OF LAND '
Since $
is a regex metacharacter (standing for the end of a logical line), you need to escape it to use as a literal '$'
. 由于
$
是正则表达式元字符(代表逻辑行的结尾),因此您需要对其进行转义以用作文字'$'
。
Might be easier to use find
: 可能更容易使用
find
:
a = '172 211 342 15/08/2017 TRANSFER OF LAND $610,000 CASH & MTGE'
b = '15/08/2017'
c = '$610,000'
a[a.find(b) + len(b):a.find(c)].strip()
'TRANSFER OF LAND'
“土地转让”
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