SQL Server：验证两列的排序顺序相同

Question

I have a table with an ID and a date column. It's possible (likely) that when a new record is created, it gets the next larger ID and the current datetime. So if I were to sort by date or I were to sort by ID, the resulting data set would be in the same order.

How do I write a SQL query to verify this?

It's also possible that an older record is modified and the date is updated. In that case, the records would not be in the same sort order. I don't think this happens.

I'm trying to move the data to another location, and if I know that there are no modified records, that makes it a lot simpler.

I'm pretty sure I only need to query those two columns: ID, RecordDate. Other links indicate I should be able to use LAG, but I'm getting an error that it isn't a built-in function name.

In other words, both https://dba.stackexchange.com/questions/42985/running-total-to-the-previous-row and Is there a way to access the "previous row" value in a SELECT statement? should help, but I'm still not able to make that work for what I want.

Answer 1

Use this:

SELECT ID, RecordDate FROM tablename t
WHERE 
  (SELECT COUNT(*) FROM tablename WHERE tablename.ID < t.ID) 
  <> 
  (SELECT COUNT(*) FROM tablename WHERE tablename.RecordDate < t.RecordDate); 

It counts for each row, how many rows have id less than the row's id and
how many rows have RecordDate less than the row's RecordDate .
If these counters are not equal then it outputs this row.
The result is all the rows that would not be in the same position after sorting by ID and RecordDate

Answer 2

If you cannot use window functions, you can use a correlated subquery and EXISTS .

SELECT *
       FROM elbat t1
       WHERE EXISTS (SELECT *
                            FROM elbat t2
                            WHERE t2.id < t1.id
                                  AND t2.recorddate > t1.recorddate);

It'll select all records where another record with a lower ID and a greater timestamp exists. If the result is empty you know that no such record exists and the data is like you want it to be.

Maybe you want to restrict it a bit more by using t2.recorddate >= t1.recorddate instead of t2.recorddate > t1.recorddate . I'm not sure how you want it.

Answer 3

the above solutions are all good but if both dates and ids are in increment then this should also work

select  modifiedid=t2.id from 
yourtable t1 join yourtable t2
on t1.id=t2.id+1 and t1.recordDate<t2.recordDate

Answer 4

One method uses window functions:

select count(*)
from (select t.*,
             row_number() over (order by id) as seqnum_id,
             row_number() over (order by date, id) as seqnum_date
      from t
     ) t
where seqnum_id <> seqnum_date;

When the count is zero, then the two columns have the same ordering. Note that the second order by includes id . Two rows could have the same date. This makes the sort stable, so the comparison is valid even when date has duplicates.