遇到困难

Question

I am trying to get the path of a directory which contains a PHP script. Let's name it script.php . It also contains included log.php .

script.php:

include_once __DIR__.'/../lib/log.php';
func();

log.php:

function func() {
   file_put_contents(__DIR__.'/log', 'Log file successfully created');
}

I execute script.php expecting the log file appear along with script.php but it doesn't happen. What happens instead is log file is being created in lib directory along with log.php file.
The only workaround I see here is to pass dir path to log.php through the function as an argument like this:

script.php:

include_once __DIR__.'/../lib/log.php';
func(__DIR__);

log.php:

function func($arg) {
   file_put_contents($arg.'/log', 'Log file successfully created');
}

Is it actually possible to get path to script.php through log.php without passing any arguments?
I just want to include the script, call a function and create new file along with script which contains include.

Answer 1

No. PHP does not make any metadata available beyond that relating to the file it is currently executing within.

What you can do to make your file paths a bit easier to deal with is define a constant in your config or header file that defines the absolute path to the root of your application. Eg:

define('APPROOT', __DIR__);

Or:

define('APPROOT', __DIR__ . '/../myapp');

Then you can define paths in your app without trying to rely on where a script happens to live, eg:

$log_file = APPROOT . '/log/foo.log';