使用SQL查找带有意外字符的电话号码

Question

I posted the same question below for SQL in Oracle here and was provided the SQL info within that works.

However, I now need to perform the same in a DB2 database and if I attempt to run the same SQL it errors out.

I need to find rows where the phone number field contains unexpected characters.

Most of the values in this field look like:

123456-7890

This is expected. However, we are also seeing character values in this field such as * and #.

I want to find all rows where these unexpected character values exist.

Expected:

1. Numbers are expected
2. Hyphen with numbers is expected (hyphen alone is not)
3. NULL is expected
4. Empty is expected

This SQL works in Oracle:

...
WHERE regexp_like(phone_num, '[^ 0123456789-]|^-|-$')

When using the same SQL above in DB2, the statement errors out.

Answer 1

I found it easiest to answer your question by phrasing a regex which matches the positive cases. Then, we can just use NOT to find the negative cases. DB2 supports a REGEXP_LIKE function:

SELECT *
FROM yourTable
WHERE
    NOT REGEXP_LIKE(phone_num, '^[0-9]+(-?[0-9]+)*$') AND
    COALESCE(phone_num, '') <> '';

Here is a demo of the regex:

Demo

Answer 2

For newer version of db2, regexp is the way to go. If you are on an older version (perhaps why you get an error), you can replace all accepted chars with '' and check if the result is an empty string. Can't check right now, but from memory, it would be

WHERE TRANSLATE(phone_num, '', '0123456789-')<>''

EDIT:

For what it's worth your regexp works for V11 so you probably have an older version of Db2. Example of translate and regexp side by side:

]$ db2 "with t(s) as ( values '123456-7890', '12345*-7890' ) 
select s, 'regexp' as method from t 
where regexp_like(s, '[^ 0123456789-]|^-|-$') 
union all 
select s, 'translate' as method 
from t where TRANSLATE(s, '', '0123456789-')<>''"

S           METHOD   
----------- ---------
12345*-7890 translate
12345*-7890 regexp   

2 record(s) selected.