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如何在java中按字符串索引的升序对列表进行排序

[英]How to sort a list in ascending order of string index in java

I've created a list in java as following:我在 java 中创建了一个列表,如下所示:

1   bbbb london
1.1 aaaa nyc
1.10 cccc jaipur
...
1.2 test test
1.11 test1 test1

I need to sort it based on index 1,1.1,1.2 etc. These are string values.我需要根据索引 1、1.1、1.2 等对其进行排序。这些是字符串值。

Like:像:

1   bbbb london
1.1 aaaa nyc
1.2 test test
...
1.10 cccc jaipur
1.11 test1 test1

How can i do that?我怎样才能做到这一点?

Initially the index was float but in-order to get 1.10 in list i changed index to string so Collection.sort(list) doesnt give output as expected.最初索引是浮动的,但为了在列表中获得 1.10,我将索引更改为字符串,因此Collection.sort(list)不会按预期提供输出。

My purpose is like to create a numbered bullets like我的目的是创建一个编号的项目符号

1 Helo
 1.1 helo1
 1.2 helo2
 1.3 hello3
2 Test
 2.1 Test1
 2.2 Test2
3 World

Any help please?有什么帮助吗?

Given the list:鉴于清单:

List<String> list = Arrays.asList("1.32   bbbb london", "21.1 aaaa nyc", 
                                  "100.10 cccc jaipur", "1.2 test test",
                                  "1.11 test1 test1");

You can write your own custom comparator as shown below:您可以编写自己的自定义比较器,如下所示:

Collections.sort(list, new Comparator<String>() {
    public int compare(String o1, String o2) {
        return Float.compare(Float.parseFloat(o1.split(" ")[0]),
                             Float.parseFloat(o2.split(" ")[0]));
    }
});

Here, we split the String by " " and fetch the floating part of the string which happens to be the first index of the array.在这里,我们用" "分割字符串并获取字符串的浮动部分,它恰好是数组的第一个索引 Now we parse it to a float and compare it with the second string.现在我们将其解析为浮点数并将其与第二个字符串进行比较。

If you are on java-8 you could do it one line:如果您使用的是java-8 ,则可以一行完成:

Collections.sort(list, (o1, o2) -> 
      Float.compare(Float.parseFloat(o1.split(" ")[0]), Float.parseFloat(o2.split(" ")[0])));

Try this.试试这个。 This should work.这应该工作。 Main logic is in compareTo method.主要逻辑在compareTo方法中。

import java.util.ArrayList;
import java.util.Collections;

public class Sort
{
  public static void main(String[] args)
  {
    ArrayList<Entry> entries = new ArrayList<>();
    entries.add(new Entry("1", "bbbb london"));
    entries.add(new Entry("1.1", "aaaa nyc"));
    entries.add(new Entry("1.10", "cccc jaipur"));
    entries.add(new Entry("1.2", "test test"));
    entries.add(new Entry("1.11", "test1 test1"));

    Collections.sort(entries);
    for (Entry e : entries)
    {
      System.out.println(e);
    }
  }
}

class Entry implements Comparable<Entry>
{
  String index;
  String value;
  int major;
  int minor;

  Entry(String index, String value)
  {
    this.index = index;
    this.value = value;

    String[] array = index.split("\\.");
    if (array.length == 2)
    {
      major = Integer.valueOf(array[0]);
      minor = Integer.valueOf(array[1]);
    }
    else if (array.length == 1)
    {
      major = Integer.valueOf(array[0]);
    }
    else
    {
      throw new IllegalArgumentException("Invalid index : " + index);
    }
  }

  @Override
  public int compareTo(Entry otherEntry)
  {
    if (this.major < otherEntry.major)
    {
      return -1;
    }
    else if (this.major > otherEntry.major)
    {
      return 1;
    }
    else
    {
      if (this.minor < otherEntry.minor)
      {
        return -1;
      }
      else if (this.minor > otherEntry.minor)
      {
        return 1;
      }
      else
      {
        return 0;
      }
    }
  }

  @Override
  public String toString()
  {
    return index + " " + value;
  }
}

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