C使用函数重写数组，避免使用指针

Question

i have searched thoroughly and could not find an answer to my question.

i would like a function in my code to rewrite an already existing array. i would like it to be local array-meaning an array that is defined and initialized inside main. i would like to execute without using pointers.

i think it should be possible because of the fact that arrays are actually pointers(as far a read).

this is my code, for what its worth:

#include<stdio.h>

void minusone_array_rewrite(int food_arr[5][2]);
int main()
{
    int food_arr[5][2] = {0};
    minusone_array_rewrite(food_arr[5][2]);

    for (int i = 0; i < 5; i++)////just printing
    {
        printf("%d", food_arr[i][0]);
        printf("%d", food_arr[i][1]);
    }
    return 0;
}

void minusone_array_rewrite(int food_arr[5][2]) {
    for (int i = 0; i < 5; i++)
    {
        food_arr[i][0] = -1;
        food_arr[i][1] = -1;
    }
}

Answer 1

Well, as you said by yourself arrays in C are pointers themselves, the problem I see is initialization of your array and passing it to function minusone_array_initializer .

The correct way would be :

#include<stdio.h>

void minusone_array_initializer(int food_arr[5][2]);
int main()
{
    int food_arr[5][2];

    minusone_array_initializer(food_arr);

    for (int i = 0; i < 5; i++) {
        printf("%d , %d \n",food_arr[i][0],food_arr[i][1]);
    }
    return 0;
}

void minusone_array_initializer(int food_arr[5][2]) {
    for (int i = 0; i < 5; i++)
    {
        food_arr[i][0] = -1;
        food_arr[i][1] = -1;
    }
 }