[英]javax.persistence.PersistenceException: No Persistence provider for EntityManager named aramis
I am new to JPA and Hibernate. 我是JPA和Hibernate的新手。 I am watching tutorials and I did every did everything mentioned from videos but I thought some errors.
我正在看教程,我做了所有视频中提到的所有事情,但我认为有些错误。
I am working with eclipse java ee. 我正在使用eclipse java ee。 And jpa,hibernate,MySQL
和jpa,休眠,MySQL
persistance: 持久性:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="aramis" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>com.webproject.web.entities.User</class>
<properties>
<property name="hibernate.connection.url" value="jdbc:mysql://localhost:3306/webproject" />
<property name="hibernate.connection.driver_class" value="com.mysql.jdbc.Driver" />
<property name="hibernate.connection.username" value="root" />
<property name="hibernate.connection.password" value="mysql123" />
</properties>
</persistence-unit>
</persistence>
user: 用户:
@Entity(name="user")
@Table(name="user")
public class User implements Serializable {
@Id
@GeneratedValue(strategy=GenerationType.AUTO)
@Column(name="id", updatable = false, nullable = false)
private int id;
private String name;
@Column(nullable=false, unique=true)
...
service: public class UserService { 服务:公共类UserService {
private EntityManagerFactory emf = Persistence.createEntityManagerFactory("aramis");
private EntityManager em = emf.createEntityManager();
private EntityTransaction tx = em.getTransaction();
private Sha512 sha512 = new Sha512();
public int insert(User user) {
Date date = new Date();
user.setCreated_at(date);
user.setRole_type(0);
String password = user.getPassword();
password = sha512.encrypt(password);
user.setPassword(password);
tx.begin();
em.persist(user);
tx.commit();
em.close();
return user.getId();
}
it's giving some error: 它给出了一些错误:
javax.persistence.PersistenceException: No Persistence provider for EntityManager named aramis
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:61)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:39)
at com.webproject.web.services.UserService.<init>(UserService.java:19)
at com.webproject.web.servlet.Register.doPost(Register.java:54)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:660)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:741)
When you call Persistence.createEntityManagerFactory("aramis")
by default it's trying to find a file called persistence.xml
inside a folder called META-INF
. 默认情况下,当您调用
Persistence.createEntityManagerFactory("aramis")
,它将尝试在名为META-INF
的文件夹中找到名为persistence.xml
的文件。
In order to make it work, you should have a META-INF/persistence.xml
in your classpath. 为了使其工作, 您应该在类路径中有一个
META-INF/persistence.xml
。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.