作为函数参数传递时如何访问`int`动态数组的数据？

Question

here in my code I'm trying to increment the value of a specific array index. The thing is when I increment it with ++ the value of it increments by 4 for some reason instead of 1. I believe the way I access the value of that index is wrong.

void updateData(char** usernames, int** userWins, int** userDraws, int** userDefeats,
    int totalUsers,char username1[],char username2[],int whoIsWinner,char againstPC){
  int i;
  printf("Username: %s.\tWins: %d.\tDraws: %d.\tDefeats: %d.\n",
      usernames[0],userWins[0],userDraws[0],userDefeats[0]);
  userWins[0]++;
  userDraws[0]++;
  userDefeats[0]++;
  printf("Username: %s.\tWins: %d.\tDraws: %d.\tDefeats: %d.\n",
      usernames[0],userWins[0],userDraws[0],userDefeats[0]);
}

userWins,userDraws,userDefeats are dynamic int arrays. I'm using ** because I want them passed by reference. Please ignore 5 last parameters of the function.

EDIT: added declaration and function call

int* userWins;
int* userDraws;
int* userDefeats;
userWins=(int*) malloc(sizeof(int)*totalUsers);
userDraws=(int*) malloc(sizeof(int)*totalUsers);
userDefeats=(int*) malloc(sizeof(int)*totalUsers);
updateData(usernames,userWins,userDraws,userDefeats,totalUsers,tempUsername1,
        tempUsername2,tempWinner,againstPC);

Answer 1

Your function takes in a double pointer, which means that in order to get the value you would have to dereference it twice. However, userWins[0] dereferences userWins once, and you get a pointer back. Then the ++ operator increments the value by the size of the pointer, which on your system is 4. If userWins is an array, simply pass it in as int* userWins .