如何使用带有参数化占位符的 sqlite3 Python 库创建 SQLite 表？

Question

From Python's documentation ( https://docs.python.org/3/library/sqlite3.html#sqlite3.Cursor.execute ), I should be able to execute SQL statements using parameterized placeholders. Yet, the code below doesn't work.

import sqlite3

conn = sqlite3.connect("temp.db")
c = conn.cursor()

c.execute("create table ? (foo text, bar text)", ("table_name",))

conn.commit()
conn.close()

I'm getting an error:

Traceback (most recent call last):
  File "main.py", line 6, in <module>
    c.execute("create table ? (foo text, bar text)", ("table_name",))
sqlite3.OperationalError: near "?": syntax error

But if I switch out of using parameterized placeholders, it works.

Answer 1

In a word - no. You can only parameterize values, not object names (in this case, the table's name). If you want to do something like this, you'd have to resort to string manipulation, eg:

c.execute("create table %s (foo text, bar text)" % ("table_name"))