替换大括号内字符串中的所有空格

Question

I need to replace all spaces in strings inside curly braces (including a prefix). Example:

From: x{Test test} test test x{Test test test } test {Test test}

To x{Test_test} test test x{Test_test_test } test {Test test}

(only applies to x{} - when curly braces include x prefix)

I can do it with help of lookhead/lookbehind but this does not work in PHP/PCRE

`(?<=x\{[^\{\}]+)\s+(?=[^\{\}]+\})`

The problem is how to do it PHP/PCRE compatible with preg_replace function?

Answer 1

You may use \\G bases regex for this:

$str = 'x{Test test} test test x{Test test test } test {Test test}';

$repl = preg_replace('/(?:x{|(?<!^)\G)[^\s}]*\K\s+(?!})/', '_', $str);
//=> x{Test_test} test test x{Test_test_test } test {Test test}

RegEx Demo

RegEx Details:

• \\G asserts position at the end of the previous match or the start of the string for the first match.
• (?:x{|(?<!^)\\G) : Matches x{ or end of previous match
• \\K : Reset current match info
• \\s+ : Match 1+ whitespace
• (?!}) : Assert we don't have an } immediate ahead