拖放-如何在dragstart事件和drop事件中获取实际的html

Question

On dragstart event I want to get the actual html of dragged element. 在dragstart事件上，我想获取拖动元素的实际html。 But when I do something like this in a dragstart event console.log( e.target); 但是当我在dragstart事件console.log( e.target);执行类似的操作时 it give me the output like this as expected; 它给了我预期的输出结果；

<p style="margin-right:72.45pt; margin-left:50.15pt; text-align:center; font-size:16pt" draggable="true"><strong>CONSULTING AND TECHNICAL SERVICES + (CATS+)</strong></p>

but this code console.log(JSON.stringify(e.target)); 但是这段代码console.log(JSON.stringify(e.target)); give me output like this ; 给我这样的输出;

{"__zone_symbol__dragstartfalse":[{"type":"eventTask","state":"running","source":"HTMLParagraphElement.addEventListener:dragstart","zone":"angular","runCount":2}]}

when send data from dragstart to drop event like this 像这样从dragstart到drop事件发送数据时

 e.dataTransfer.setData('Id', e.target);

and then catch data from e.dataTransfer in drop event 然后在放置事件中从e.dataTransfer捕获数据

 let sourceElement = event.dataTransfer.getData("Id");
    console.log((sourceElement).innerHTML);
    console.log((sourceElement).outerHTML);

I end up with this output [object HTMLParagraphElement] Now , how I convert this [object HTMLParagraphElement] into a presentable HTML on UI as I tried .innerHTML and .outerHTML but it gives me undefined on screen rather proper output. 我最终得到此输出[object HTMLParagraphElement]现在，当我尝试使用.innerHTML and .outerHTML ，如何将[object HTMLParagraphElement]转换为UI上可显示的HTML，但它给了我在屏幕上未定义的正确输出。

Answer 1

I would suggest the bottom approach to do this type of things. 我建议采用底层方法来执行此类操作。

<!DOCTYPE HTML>
<html>
<head>
<script>
function allowDrop(ev) {
  ev.preventDefault();
}

function drag(ev) {
  ev.dataTransfer.setData("text", ev.target.id);
}

function drop(ev) {
  ev.preventDefault();
  var data = ev.dataTransfer.getData("text");
  ev.target.appendChild(document.getElementById(data));
}
</script>
</head>
<body>

<div id="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div>

<img id="drag1" src="img_logo.gif" draggable="true"
ondragstart="drag(event)" width="336" height="69">

</body>
</html>

Answer 2

In dragestart event use this 在dragestart事件中使用此

e.dataTransfer.setData('text/html', e.currentTarget.outerHTML);

Instead of 代替

e.dataTransfer.setData('Id', e.target);

While in drop event you will get the HTML string. 在放置事件中，您将获得HTML字符串。 Convert that string into an HTML element as follow 将该字符串转换为HTML元素，如下所示

  let sourceElement = event.dataTransfer.getData("text/html");
    let doc: any = new DOMParser().parseFromString(sourceElement, "text/html");
    var clonedSourceHtmlElement: HTMLElement = <HTMLElement>(<HTMLElement>doc.firstChild.children[1].children[0]).cloneNode(true);

拖放-如何在dragstart事件和drop事件中获取实际的html

问题描述

2 个解决方案

解决方案1
0 2018-12-31 10:43:40

解决方案2
0 已采纳 2019-01-02 14:22:22

拖放-如何在dragstart事件和drop事件中获取实际的html

问题描述

2 个解决方案

解决方案1 0 2018-12-31 10:43:40

解决方案2 0 已采纳 2019-01-02 14:22:22

解决方案1
0 2018-12-31 10:43:40

解决方案2
0 已采纳 2019-01-02 14:22:22