SQL SELECT，其中单元格为一定长度并包含特定字符

Question

I'm trying to create a SELECT statement that selects rows where NAME is max. 5 characters and the . is in the NAME. I only want the first, so I'm including a LIMIT 1 to the statement.

I have worked with the following

searchstring = "."
sql = "SELECT * FROM Table WHERE NAME LIKE %s LIMIT 1"
val = (("%"+searchstring+"%"),)
cursor.execute(sql, val)

But I'm not sure how to incorporate the length of NAME in my statement.

My "Table" is as follows:

ID     NAME
1      Jim
2      J.
3      Jonathan
4      Jack M.
5      M.S.

So based on the table above, I would expect row 2 and 5 to be selected. I could select all, and loop through them. But as I only want the first, I'm thinking I would prefer a SQL statement?

Thanks in advance.

Answer 1

您可以将CHAR_LENGTH函数与LIKE一起使用：

SELECT * FROM Table WHERE name LIKE '%.%' AND CHAR_LENGTH(name) <= 5 LIMIT 1

Answer 2

Try LEN() Select LEN( result string ); This will return the length of string. but this will count spaces also. Try removing it with LTRIM().

Answer 3

Oracle SQL

SELECT * FROM Table WHERE name LIKE '%.%' AND LENGTH(name) < 6 and rownum < 2

Base on the sql language(oracle, mysql, sql server, etc) use

length() or char_length()

rownum or limit