在遇到换行符或逗号时拆分/剥离一组行

Question

I have a set of lines in a textpad.

Eg:

643 ABCF aksdjgk 1q25hgn
239056 dsgkn 32968, 39859 ewktgklh, 35927369
9689846 dklsghdkls 23-608 dsklgnk
ewth834056 sidtguoi,235907 sdkgji,25689-8, 29067490,wtyuoew

How can I read this using python and have the text split into different list values on newline as well as , (comma)?

For instance, the output for the example text should come out as

643 ABCF aksdjgk 1q25hgn
239056 dsgkn 32968,
39859 ewktgklh,
35927369
9689846 dklsghdkls 23-608 dsklgnk
ewth834056 sidtguoi,
235907 sdkgji,
25689-8,
29067490,
wtyuoew

Answer 1

Try using re.sub , and replace all commas with comma followed by a newline:

result = re.sub(',\s*', ',\n', input)

Note that we actually match ,\\s* , to remove any whitespace which might occur after a comma separator.

Answer 2

Assuming that "textpad" means text file, you have a couple of options. For a small file like the one shown, the easiest solution would be to read in the entire file as a string, and replace the commas with a comma + newline, as @TimBiegeleisen's answer shows.

For larger files, this may not be a good option due to memory constraints. In that case, and for the sake of generality, I like to iterate over the lines of a file. Here is a fairly simple generator that behaves like a normal file iterator, but also splits on commas:

from itertools import zip_longest, repeat
import re

def spliterator(file):
    for line in file:
        segments = re.split(r',\s*', line)
        ends = repeat(',\n', len(segments) - 1)
        for item in zip_longest(segments, ends, fillvalue=''):
            yield ''.join(item)

It would be pretty simple to make this accept the split pattern as an argument, optionally keep the trailing spaces, and return the whole line with newline characters inserted.

Using the generator is simple, since it just wraps a normal file object or any other iterable of lines:

with open('textpad.txt') as file:
    print(''.join(spliterator(file)))

Here is an IDEOne link with a demo.

To get the contents of the whole file as though read in by readlines , just wrap in list :

lines = list(spliterator(file))

To write back to an open output file, use writelines directly:

output.writelines(spliterator(file))