[英]Why is std::filesystem::u8path deprecated in c++20?
Introduced in c++17, std::filesystem::u8path
seems to be deprecated in c++20.在 c++17 中引入,
std::filesystem::u8path
似乎在 c++20 中被弃用。
What is the reason for this choice?这个选择的原因是什么? What should I use in c++17?
我应该在 c++17 中使用什么? What should I use in c++20?
我应该在 c++20 中使用什么?
Because, thanks to the existence of the C++20 feature char8_t
, this will work:因为,由于 C++20 特性
char8_t
的存在,这将起作用:
path p(u8"A/utf8/path");
u8path
existed to allow the detection of the difference between a UTF-8 string and a narrow character string. u8path
存在允许检测 UTF-8 字符串和窄字符串之间的差异。 But since C++20 will give us an actual type for that, it is no longer necessary.但由于 C++20 将为我们提供一个实际的类型,它不再是必要的。
What should I use in c++17?
我应该在 c++17 中使用什么?
Use u8path
.使用
u8path
。 Deprecation does not mean removed or inaccessible .弃用并不意味着已删除或无法访问。 It merely means subject to eventual removal.
它仅仅意味着最终会被移除。
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