修剪Awk中的前导和尾随空格

Question

I have a file which contains 1 line like below

 VINOTH                                                                                    |KARTHICK                                                                                       |RAVI

I'm using the below command to remove the leading and trailing spaces , but it's not not working.

awk '{ gsub(/^[ \t]+|[ \t]+$/, ""); print }' Input_File

Please help.

Required Output.

VINOTH|KARTHICK|RAVI

Answer 1

You may use

sed 's/[ \t]*|[ \t]*/|/g;s/^[ \t]*\|[ \t]*$//g' Input_File

There are two regexps here:

• s/[ \\t]*|[ \\t]*/|/g replaces all | enclosed with optional whitespaces with a single | (the | in the regex matches a literal | char as per BRE POSIX standard)
• s/^[ \\t]*\\|[ \\t]*$//g removes all whitespaces at the start and end of lines. Note that \\| here is an OR operator (escaped because the BRE POSIX syntax is used).

See the online demo .

Answer 2

您能否请尝试执行以下操作（由于您的示例输入和预期输出不清楚，因此未对其进行测试）。

awk '{gsub(/^[[:space:]]+|[[:space:]]+$/,"")} 1'  Input_file