[英]Can't find REST resource
So i'm trying to develop web app which has Java Class names "Service.java" which is my REST Service. 因此,我正在尝试开发具有Java类名称“ Service.java”的Web应用程序,这是我的REST服务。
@Path("/service")
public class Service {
@Context
HttpServletRequest request;
@Context
ServletContext ctx;
@GET
@Path("/getJustAdministrators")
@Produces(MediaType.APPLICATION_JSON)
public Collection<Administrator> getJustAdministrators() {
System.out.println("get administrators");
return getAdministrators().getValues();
}
private Administrators getAdministrators() {
Administrators administrators = (Administrators) ctx
.getAttribute("administrators");
if (administrators == null) {
administrators = new Administrators(ctx.getRealPath(""));
ctx.setAttribute("administrators", administrators);
}
return administrators;
}
My main.js file, which is linked to my welcome page, looks like this: 我的main.js文件链接到我的欢迎页面,如下所示:
var rootURL1 = "../eTicket/rest/service/getJustAdministrators";
loadAdministrators();
function loadAdministrators() {
console.log('loadAdministrators');
$.ajax({
type : 'GET',
url : rootURL1,
dataType : "json", // data type of response
success : function(data) {
alert(data);
}
});
}
And i get error in 'inspect' like this: 我在这样的“检查”中遇到错误:
http://localhost:8080/eTicket/rest/service/getJustAdministrators 404 (Not Found) http:// localhost:8080 / eTicket / rest / service / getJustAdministrators 404(未找到)
My web.xml file looks like this: 我的web.xml文件如下所示:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>eTicket</display-name>
<welcome-file-list>
<welcome-file>start.html</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>Jersey REST Service</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>eTicket</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Jersey REST Service</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
Why it can't find my resource method?? 为什么找不到我的资源方法?
Your sub-path may be trying to bind to the root, just like /service is. 您的子路径可能试图绑定到根目录,就像/ service一样。
@Path("/getJustAdministrators")
You may want: 您可能想要:
@Path("getJustAdministrators")
Or: 要么:
@Path("./getJustAdministrators")
Or even more explicitly: 或更明确地说:
@Path("/service/getJustAdministrators")
The definition of your servlet class is not correct: 您的Servlet类的定义不正确:
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
It should be pointing to your Service.java class. 它应该指向您的Service.java类。
Please use this page as reference: 请使用此页面作为参考:
https://docs.oracle.com/cd/E13222_01/wls/docs92/webapp/configureservlet.html https://docs.oracle.com/cd/E13222_01/wls/docs92/webapp/configureservlet.html
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