[英]Google Sheets: Move Row to Other Sheet, Then Back Again, Based on Cell Value
Please please help! 请帮忙! I have been researching this for weeks without a solution. 我已经对此进行了数周的研究,没有解决方案。
We use google forms to combine data onto google sheets. 我们使用Google表单将数据合并到Google表格中。 There are 2 sheets- "INCOMPLETE" which accepts all form responses, and "COMPLETE". 有2张纸-“不完整”接受所有表单响应,“不完整”。
I was able move a row based on the condition "COMPLETE" from sheet name "INCOMPLETE" to sheet name "COMPLETE". 我能够根据条件“ COMPLETE”从工作表名称“ INCOMPLETE”移动到工作表名称“ COMPLETE”。
I need help with: (1) I can not for the life of me find a script that will reverse it if someone accidentally checked "COMPLETE", therefore, moving it back to the "INCOMPLETE" Sheet and have it sorted by Time Stamp. 我需要以下方面的帮助:(1)如果有人不小心检查了“ COMPLETE”,我将无法找到一个可以将其反转的脚本,因此,将其移回“ INCOMPLETE”表并按时间戳进行排序。
(2) If possible I would also like another column that shows a timestamp for each time an update is made to that particular row. (2)如果可能,我还希望另一列显示每次对该特定行进行更新时的时间戳。
(3) If possible, send a reminder email to the order person when a incomplete remains for more than 2 days (from the original timestamp). (3)如果可能的话,如果残缺不全超过2天(从原始时间戳记起),请向订购者发送提醒电子邮件。
This is the script that I have so far: 这是我到目前为止的脚本:
function onChange() { // moves a row from a sheet to another when a magic value is entered in a column // adjust the following variables to fit your needs // see https://productforums.google.com/d/topic/docs/ehoCZjFPBao/discussion var sheetNameToWatch = "INCOMPLETE"; var sheetNameToWatch2 = "COMPLETE"; var columnNumberToWatch = 7; // column A = 1, B = 2, etc. var valueToWatch = "COMPLETE"; var valueToWatch2 = "INCOMPLETE"; var sheetNameToMoveTheRowTo = "COMPLETE"; var sheetNameToMoveTheRowTo2 = "INCOMPLETE"; var ss = SpreadsheetApp.getActiveSpreadsheet(); var sheet = SpreadsheetApp.getActiveSheet(); var range = sheet.getActiveCell(); if (sheet.getName() == sheetNameToWatch && range.getColumn() == columnNumberToWatch && range.getValue() == valueToWatch) { var targetSheet = ss.getSheetByName(sheetNameToMoveTheRowTo); var targetRange = targetSheet.getRange(targetSheet.getLastRow() + 1, 1); sheet.getRange(range.getRow(), 1, 1, sheet.getLastColumn()).copyTo(targetRange); sheet.deleteRow(range.getRow()); } else if (sheet.getName() === sheetNameToWatch2 && range.getColumn() == columnNumberToWatch && range.getValue() == valueToWatch) { var targetSheet = ss.getSheetByName(sheetNameToMoveTheRowTo2); var targetRange = targetSheet.getRange(targetSheet.getLastRow() + 1, 1); sheet.getRange(range.getRow(), 1, 1, sheet.getLastColumn()).copyTo(targetRange); sheet.deleteRow(range.getRow()); } }
During the testing of this I found the bugs I left as a comment above. 在测试过程中,我发现了上面作为评论留下的错误。 I also like to add a return to other sheets as quickly as possible so that the code returns on unwanted sheets as quickly as possible. 我还想尽快将返回值添加到其他工作表中,以使代码尽快返回到不需要的工作表上。
function onChange() {
var ss=SpreadsheetApp.getActive();
var sh=ss.getActiveSheet();
var rg=sh.getActiveRange();
Logger.log('Head: Sheet: %s Range: %s col: %s row: %s value: %s',sh.getName(),rg.getA1Notation(),rg.getColumn(),rg.getRow(),rg.getValue());
if(sh.getName()=='INCOMPLETE' || sh.getName()=='COMPLETE'){
if(sh.getName()=='INCOMPLETE' && rg.getColumn()==7 && rg.getValue()=='COMPLETE') {
var tsh=ss.getSheetByName('COMPLETE');
var trg=tsh.getRange(tsh.getLastRow() + 1, 1);
sh.getRange(rg.getRow(), 1, 1, sh.getLastColumn()).copyTo(trg);
sh.deleteRow(rg.getRow());
Logger.log('Top: Sheet: %s Range: %s col: %s row: %s',sh.getName(),rg.getA1Notation(),rg.getColumn(),rg.getRow());
}
if (sh.getName()=='COMPLETE' && rg.getColumn()==7 && rg.getValue()=='INCOMPLETE') {
var tsh=ss.getSheetByName('INCOMPLETE');
var trg=tsh.getRange(tsh.getLastRow() + 1, 1);
sh.getRange(rg.getRow(), 1, 1, sh.getLastColumn()).copyTo(trg);
sh.deleteRow(rg.getRow());
Logger.log('Bot: Sheet: %s Range: %s col: %s row: %s',sh.getName(),rg.getA1Notation(),rg.getColumn(),rg.getRow());
}
}else{
return;//quick return for other sheets
}
}
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