正则表达式-查找除某些模式以外的所有唯一字符串

Question

I would like to find all unique strings in my JavaScript project. I'm using WebStorm to search for it and I have this in terms of my search:

'.*' // any number of quoted characters

This does get me all the strings in the project but I would like to exclude some and am not sure how to.

I get results like import s and require s which I would like to exclude:

const _ = require('lodash');
and
import React from 'react';

What could I enter for a search to exclude that from my results?

Answer 1

尝试这样的否定前瞻(?!require)(?!import)('.*') ，它似乎产生了我想要的结果

Answer 2

I don't think the regex you posted in your answer (?!require)(?!import)('.*') works:

 const tests = [ "const _ = require('lodash');", "import React from 'react';", "some other 'string'" ]; tests.forEach(test => { console.log(/(?!require)(?!import)('.*')/.test(test)); }); 

Negative lookbehind works:

 const tests = [ "const _ = require('lodash');", "import React from 'react';", "some other 'string'" ]; tests.forEach(test => { console.log(/(?<!(require|import).*)'.+'/.test(test)); }); 

Caveat: I believe negative lookbehind is currently only supported in Chrome